问题描述
我有一张桌子,上面有我所有顾客的购买物。我想选择上周(从星期日开始的一周)中的所有条目。
I have a table which has all the purchases of my costumers. I want to select all entries from the last week, (week start from Sunday).
id value date
5907 1.20 "2015-06-05 09:08:34-03"
5908 120.00 "2015-06-09 07:58:12-03"
我已经尝试过:
SELECT id, valor, created, FROM compras WHERE created >= now() - interval '1 week' and parceiro_id= '1'
但是我获得了上周的数据,包括本周的数据,我只想要上周的数据。
But I got the data from the last week including data from this week, I only want data from the last week.
如何仅从上周获得数据?
How to get data only from last week ?
推荐答案
此条件将返回上周日至周六的记录:
This condition will return records from Sunday till Saturday last week:
WHERE created BETWEEN
NOW()::DATE-EXTRACT(DOW FROM NOW())::INTEGER-7
AND NOW()::DATE-EXTRACT(DOW from NOW())::INTEGER
有一个例子:
WITH compras AS (
SELECT ( NOW() + (s::TEXT || ' day')::INTERVAL )::TIMESTAMP(0) AS created
FROM generate_series(-20, 20, 1) AS s
)
SELECT to_char( created, 'DY'::TEXT), created
FROM compras
WHERE created BETWEEN
NOW()::DATE-EXTRACT(DOW FROM NOW())::INTEGER-7
AND NOW()::DATE-EXTRACT(DOW from NOW())::INTEGER
@ d456:
那右边, BETWEEN
包括午夜在间隔的两端的星期日。要在间隔结束时排除周日的午夜,必须使用运算符> =
和<
:
That right, BETWEEN
includes midnight on Sunday at both ends of the interval. To exclude midnight on Sunday at end of interval it is necessary to use operators >=
and <
:
WITH compras AS (
SELECT s as created
FROM generate_series( -- this would produce timestamps with 20 minutes step
(now() - '20 days'::interval)::date,
(now() + '20 days'::interval)::date,
'20 minutes'::interval) AS s
)
SELECT to_char( created, 'DY'::TEXT), created
FROM compras
WHERE TRUE
AND created >= NOW()::DATE-EXTRACT(DOW FROM NOW())::INTEGER-7
AND created < NOW()::DATE-EXTRACT(DOW from NOW())::INTEGER
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