本文介绍了尽管出现在受信任的包列表中,但该类不在受信任的包中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我试图在没有任何特殊设置的情况下在 2 个不同的 Spring Boot 应用程序之间实现简单的 Kafka 通信,该应用程序只有一个 kafkalistener.我给消费者的 yml 如下:
I am trying to implement a simple Kafka communication between 2 different Spring Boot applications with out any special settings, this application has only one kafkalistener. My yml for the consumer is the following:
spring:
kafka:
bootstrap-servers: ip_here
topic:
json: topic_here
consumer:
group-id: group_id
auto-offset-reset: earliest
value-deserializer: org.springframework.kafka.support.serializer.JsonDeserializer
properties:
spring:
json:
trusted:
packages: 'com.example.kw.dtos.Classdata'
我收到的错误如下:
Caused by: java.lang.IllegalArgumentException: 类'com.example.kw.dtos.Classdata' 不在受信任的包中:[java.util、java.lang、com.example.kw.dtos.Classdata].如果你相信这个类可以安全地反序列化,请提供它的名称.如果序列化仅由受信任的来源完成,您也可以启用相信所有人 (*).
该软件包在受信任的软件包中,但出了点问题.
The package is in the trusted packages but something is wrong.
我的工厂类:
@Configuration
@EnableKafka
public class MsgListener {
@Value("${spring.kafka.bootstrap-servers}")
private String bootstrapServers;
@Bean
public Map<String, Object> consumerConfigs() {
Map<String, Object> props = new HashMap<>();
props.put(ConsumerConfig.BOOTSTRAP_SERVERS_CONFIG, bootstrapServers);
props.put(ConsumerConfig.KEY_DESERIALIZER_CLASS_CONFIG, StringDeserializer.class);
props.put(ConsumerConfig.VALUE_DESERIALIZER_CLASS_CONFIG, JsonDeserializer.class);
props.put(ConsumerConfig.GROUP_ID_CONFIG, "json");
props.put(ConsumerConfig.AUTO_OFFSET_RESET_CONFIG, "earliest");
props.put(JsonDeserializer.TRUSTED_PACKAGES, "com.example.kw.dtos.Classdata");
return props;
}
@Bean
public ConsumerFactory<String, Classdata> consumerFactory() {
return new DefaultKafkaConsumerFactory<>(
consumerConfigs(),
new StringDeserializer(),
new JsonDeserializer<>(Classdata.class));
}
@Bean
public ConcurrentKafkaListenerContainerFactory<String, Classdata> kafkaListenerContainerFactory() {
ConcurrentKafkaListenerContainerFactory<String, Classdata> factory =
new ConcurrentKafkaListenerContainerFactory<>();
factory.setConsumerFactory(consumerFactory());
return factory;
}
}
推荐答案
应该只是包 com.example.kw.dtos
String packageName = ClassUtils.getPackageName(requestedType).replaceFirst("\\[L", "");
for (String trustedPackage : this.trustedPackages) {
if (packageName.equals(trustedPackage)) {
return true;
}
}
这篇关于尽管出现在受信任的包列表中,但该类不在受信任的包中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!