如何在python中测试一个单词是否为单数形式?

问题描述

我试图通过使用 nltk pos_tag 来获取单词是单数形式还是复数形式.但结果并不准确.

I am trying to get whether a word is in singular form or in plural form by using nltk pos_tag. But the results are not accurate.

那么，我需要一种方法来找到如何获得一个单词是单数形式还是复数形式?而且我不需要使用任何 python 包就需要它.

So, I need a way to find how can get whether a word is in singular form or in plural form? moreover I need it without using any python package.

推荐答案

对于英语，每个词都应该有一个词根词条，其中默认的复数是单数.

For English, every word should somehow have a root lemma where the default plurality is singular.

假设你的列表中只有名词，你可以试试这个:

Assuming that you have only nouns in your list, you can try this:

from nltk.stem import WordNetLemmatizer

wnl = WordNetLemmatizer()

def isplural(word):
    lemma = wnl.lemmatize(word, 'n')
    plural = True if word is not lemma else False
    return plural, lemma

nounls = ['geese', 'mice', 'bars', 'foos', 'foo',
                'families', 'family', 'dog', 'dogs']

for nn in nounls:
    isp, lemma = isplural(nn)
    print nn, lemma, isp

你会遇到wordnet外的问题，那么你必须使用更复杂的分类器 或 有限状态机 来自 NLTK.

You will have a problem when word is out of wordnet, then you have to use more sophiscated classifier or finite state machines out of NLTK.

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