.getLocationInWindow(int[] location)

一个控件在其父窗体中的坐标位置

.getLocationOnScreen(int[] location)

一个控件在其整个屏幕上的坐标位置

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getLocationInWindow是以B为原点的C的坐标

getLocationOnScreen以A为原点。

以下是getLocationOnScreen演示样例

start = (Button) findViewById(R.id.start);
int []location=new int[2];
start.getLocationOnScreen(location);
int x=location[0];//获取当前位置的横坐标
int y=location[1];//获取当前位置的纵坐标

以下是getLocationInWindow演示样例

start = (Button) findViewById(R.id.start);
int []location=new int[2];
start.getLocationInWindow(location);
int x=location[0];//获取当前位置的横坐标
int y=location[1];//获取当前位置的纵坐标

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 附上源码

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.getLocationInWindow(int[] location)

/**
* <p>Computes the coordinates of this view in its window. The argument
* must be an array of two integers. After the method returns, the array
* contains the x and y location in that order.</p>
*
* @param location an array of two integers in which to hold the coordinates
*/
public void getLocationInWindow(int[] location) {
if (location == null || location.length < 2) {
throw new IllegalArgumentException("location must be an array of two integers");
} if (mAttachInfo == null) {
// When the view is not attached to a window, this method does not make sense
location[0] = location[1] = 0;
return;
} float[] position = mAttachInfo.mTmpTransformLocation;
position[0] = position[1] = 0.0f; if (!hasIdentityMatrix()) {
getMatrix().mapPoints(position);
} position[0] += mLeft;
position[1] += mTop; ViewParent viewParent = mParent;
while (viewParent instanceof View) {
final View view = (View) viewParent; position[0] -= view.mScrollX;
position[1] -= view.mScrollY; if (!view.hasIdentityMatrix()) {
view.getMatrix().mapPoints(position);
} position[0] += view.mLeft;
position[1] += view.mTop; viewParent = view.mParent;
} if (viewParent instanceof ViewRootImpl) {
// *cough*
final ViewRootImpl vr = (ViewRootImpl) viewParent;
position[1] -= vr.mCurScrollY;
} location[0] = (int) (position[0] + 0.5f);
location[1] = (int) (position[1] + 0.5f);
}

.getLocationOnScreen(int[]
location)

  /**
* <p>Computes the coordinates of this view on the screen. The argument
* must be an array of two integers. After the method returns, the array
* contains the x and y location in that order.</p>
*
* @param location an array of two integers in which to hold the coordinates
*/
public void getLocationOnScreen(int[] location) {
getLocationInWindow(location); final AttachInfo info = mAttachInfo;
if (info != null) {
location[0] += info.mWindowLeft;
location[1] += info.mWindowTop;
}
}



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  作者:欧阳鹏  欢迎转载,与人分享是进步的源泉!

  转载请保留原文地址:http://blog.csdn.net/ouyang_peng

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我的Android进阶之旅------&amp;gt;android中getLocationInWindow 和 getLocationOnScreen的差别-LMLPHP

 

05-29 00:47