问题描述
如果我有以下代码，是否复制了矢量?
If I have the following code, is the vector copied?
std::vector<int> x = y.getTheVector();
还是取决于getTheVector()的返回类型是否是引用?
or would it depend on whether the return type of getTheVector() is by reference?
或者我只需要使用:
std::vector<int>& x = y.getTheVector();
或者，我需要两者都做吗?
or, would I need to do both?
推荐答案
std::vector<int> x = y.getTheVector();
不管y.getTheVector();的返回类型如何，
始终进行复制.
always makes a copy, regardless of the return type of y.getTheVector();.
std::vector<int>& x = y.getTheVector();
不会复制.但是，只要y.getTheVector()返回对该函数返回后将是有效的对象的引用，则x将有效.如果y.getTheVector()返回在函数中创建的对象，则x将指向在语句后不再有效的对象.
would not make a copy. However, x will be valid as long as y.getTheVector() returns a reference to an object that is going to be valid after the function returns. If y.getTheVector() returns an object created in the function, x will point to an object that is no longer valid after the statement.
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