需要帮助我的魔方计划:(

本文介绍了需要帮助我的魔方计划:(的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 我一直在努力学习这个项目，我并没有取得任何成功。 我制作了一个二维数组，但是当我输入一个数字时，我得到一个很大的数字有一个 - 在它面前。我甚至不知道使用什么算法来使Magic Square的对角线彼此相等。这是我的源代码：I've been working hard on this program and I'm not really making any success.I made a two-dimensional array, but when I input a number I just get a large number with a - in front of it. I don't even know what algorithms to use to make the Magic Square's diagonals equal to one another. Here's my source code:#include<fstream>#include<iomanip>using namespace std;ofstream outfile;int main(){outfile.open("output.txt");int n; //intermediate variables and array information storecout << "Welcome to Magic Square Program!" << endl << endl;cout << "Enter order of the magic box: ";cin >> n;int MagicSquare[5][5];MagicSquare[0][2] = 1;for (int x = 0; x < n; x++){for (int y = 0; y < n; y++){cout << setw(3) << x * y << MagicSquare[x][y];}cout << endl;}system("pause");return 0;}推荐答案 Quote： cout<< setw（3）<< x * y<< MagicSquare [x] [y];cout << setw(3) << x * y << MagicSquare[x][y];所有 MagicSquare 数组，但 MagicSquare [0] [2] item未初始化，因此你在那里得到垃圾。all the MagicSquare array but the MagicSquare[0][2] item is uninitialized, hence you are getting garbage there.MagicSquare[x][y] = x * y;，然后才能访问它。 和我告诉你检查n是否低于5或分配内存before accessing it.And a I told you check that n is below 5 or allocate memoryint *MagicSquare = new int[n*n];//at the endedelete MagicSquare;// 这篇关于需要帮助我的魔方计划:(的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！