问题描述
我建立了一个二进制'foo'.我现在希望将可执行文件链接到动态库"bar".如何将foo链接到bar?(使用ld或任何其他方式).我不想在OSX上使用DYLIB_INSERT_PATH或在Linux上使用等效的LD_PREOAD.
I have built a binary 'foo'. I now want the executable to be a linked to a dynamic library 'bar'. How can I link foo to bar?(using ld or any other way). I don't want to use DYLIB_INSERT_PATHon OSX or its equivalent LD_PREOAD on Linux.
我想在OSX上执行此操作，但这是一个通用的问题.
I want to do this on OSX, but this question is a generic one.
推荐答案
您打算做什么?
链接过程解析符号:它满足需求.
The link process resolves symbols: it provide satisfactions to needs.
如果可执行文件不需要动态库提供的任何符号，则链接程序将完全丢弃它.
If the executable doesn't need any symbols offers by the dynamic library, the linker will entirely discard it.
您可以将动态库替换为另一个动态库，但是当动态库不存在时，您将无法解决该需求.
You may replace a dynamic library by another one but you can't resolve a need when it doesn't exists.
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