本文介绍了如何自动设置下拉列表的大小?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我试图用Greasemonkey编写一个脚本,该脚本将自动根据选择选项的数量设置下拉列表的大小(可以有多个...),但是由于我有限的JavaScript知识,我不知道真的不知道该怎么做.
I'm trying to write a script in Greasemonkey that will automatically set the size of Drop-down lists (there can be more than one...) on the number of selection options, but with my limited JavaScript knowledge I don't really know how to do this.
主题示例:
<select name="z_pos_id">
<option value="2463">Option A</option>
<option value="2609">Option B</option>
<option value="3013">Option C</option>
</select>
<select name="z_pos_id">
<option value="140">Option AA</option>
<option value="3038">Option AB</option>
<option value="3519">Option AC</option>
<option value="2645">Option AD</option>
</select>
所需输出示例:
<select size="3" name="z_pos_id">
<option value="2463">Option A</option>
<option value="2609">Option B</option>
<option value="3013">Option C</option>
</select>
<select size="4" name="z_pos_id">
<option value="140">Option AA</option>
<option value="3038">Option AB</option>
<option value="3519">Option AC</option>
<option value="2645">Option AD</option>
</select>
因此,<select name="z_pos_id">
应替换为:
So, <select name="z_pos_id">
should be replace with this:
<select size="*the number of options*" name="z_pos_id">
谢谢大家的帮助!
推荐答案
这是一个完整的脚本.这应该是很自我解释的:
Here's a complete script. It should be fairly self explanatory:
// ==UserScript==
// @name _Auto-size select selects.
// @include http://YOUR_SERVER.COM/YOUR_PATH/*
// @grant none
// ==/UserScript==
var posIdSelects = document.querySelectorAll ("select[name=z_pos_id]");
for (var J = posIdSelects.length - 1; J >= 0; --J) {
var numOpts = posIdSelects[J].getElementsByTagName ("option").length;
posIdSelects[J].setAttribute ("size", numOpts);
}
这篇关于如何自动设置下拉列表的大小?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!