从ARGB1555位图转换为RGB8888

问题描述

有一点脑屁的权利，但我需要帮助从ARGB1555将图像转换为RGB8888。

Having a bit of a brain fart right now, but I'm needing help converting an image from ARGB1555 to RGB8888.

我已经拥有了通过每个像素（读取基本的文件u16s）的那张循环，我想将它们存储为U32来代替。我想我只想用一些二进制运算符来获得2-6，7-11，12-16位，然后用另算每种颜色哪里更改各自RGB8888价值......但我真的穿上'知道如何做到这一点。

I already have the loop that goes through each of the pixels (reads u16s from a file essentially), and I would like to store them as a u32 instead. I'd suppose I would just use some binary operator to get the 2-6, 7-11, and 12-16 bits, then use another operator to somehow change each color to their respective RGB8888 value... but I really don't know how to do this.

推荐答案

您剪掉状态是什么语言你写它，但这里是一个C ++函数吧：
它需要在ARGB1555 16位整数，并在ARGB8888返回一个32位的整数

You didnt state what language you are writing it in but here is a C++ function for it:It takes the 16 bit integer in ARGB1555 and returns a 32 bit integer in ARGB8888

unsigned int ARGB1555toARGB8888(unsigned short c)
{
    const unsigned int a = c&0x8000, r = c&0x7C00, g = c&0x03E0, b = c&0x1F;
    const unsigned int rgb = (r << 9) | (g << 6) | (b << 3);
    return (a*0x1FE00) | rgb | ((rgb >> 5) & 0x070707);
}

参考：

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