本文介绍了OpenThread支持多少跳?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

作为网格,信号可以在设备之间传播.自然地,必须有一个跳数限制.OpenThread支持多少个节点跃点?

As a mesh, a signal can propagate across devices. Naturally there must be a hop limit. How many node hops does OpenThread support?

推荐答案

线程允许的线程路由器的最大路径成本为16.路由器之间的可用链接成本可能在1到4之间,最好是1.结果,具有良好链接的路由器之间的最大跳数为16.考虑到到终端设备的链接不包括在路由成本中,可以在路由器路径的每一端添加另一个跳数,从而使实际操作变得困难.限制18个跃点.任何一条或多条链路成本大于1的路径都会减少最大跳数.

The maximum path cost amount Thread Routers allowed by Thread is 16. Usable link costs between Routers may range from 1 to 4, with 1 being the best. As a result, the maximum number of hops between Routers with good links is 16. Considering that links to end devices are not included in the route cost, it is possible to add another hop at each end of the Router path, making the actual hard limit 18 hops. Any paths that have one or more link costs greater than 1 will reduce the maximum hop count.

这篇关于OpenThread支持多少跳?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

09-09 11:02