本文介绍了R中的高效编程的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有类似
author_id paper_id confirmed author_name1 author_affiliation1 author_name
826 25733 1 Emanuele Buratti Genetic engineering Emanuele Buratti
826 25733 1 Emanuele Buratti International center Emanuele Buratti
826 47276 1 Emanuele Buratti Emanuele Buratti
826 77012 1 Emanuele Buratti Emanuele Buratti
826 77012 1 Emanuele Buratti Emanuele Buratti
826 79468 1 Emanuele Buratti Emanuele Buratti
author_affiliation
Genetic enginereing
The International Centre for Genetic Engineering and Biotechnology, Padriciano 66,
Trieste, Italy
International Centre for Genetic Engineering and Biotechnology, Padriciano 99, 34149
Trieste, Italy
现在,我必须检查author_name和author_name1(name_dist)之间的每一行strindist以及author_affiliation与author_affiliation1(aff_sit.)之间的stringdist.
Now I have to check for each row strindist between author_name and author_name1(name_dist) and the stringdist between author_affiliation vs author_affiliation1(aff_sit.
我正在使用
name_dist<-vector()
aff_dist<-vector()
for(i in 1:nrow(mer1))
{
name_dist[i]<-stringdist(mer1$author_name1[i],mer1$author_name[i],method="lv")
aff_dist[i]<-stringdist(mer1$author_affiliation1[i],mer1$author_affiliation[i],method="lv")
}
但这会花费很多时间.如何有效地做到这一点?
But this is using a lot of time.How could this be done efficiently?
谢谢
推荐答案
您可以直接对其矢量化
i=1:nrow(mer1)
name_dist<-stringdist(mer1$author_name1[i],mer1$author_name[i],method="lv")
aff_dist<-stringdist(mer1$author_affiliation1[i],mer1$author_affiliation[i],method="lv")
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