使用Apache CXF 2.4 JAX-RS和Spring Security 3.2获取用户名

问题描述

我使用 SecurityContextHolder 在我的JAX-RS资源中获取用户名，并且可以正常工作：

I get the user name in my JAX-RS resource with SecurityContextHolder and that works:

@Path("/myresource")
public class MyResoure {

     @Get
     public String getUserName() {
          return SecurityContextHolder.getContext().getAuthentication().getName();
     }
}

但我想将SecurityContext注入类字段（编写JUnit测试）。我尝试了一些记录的方法：

But I want to inject the SecurityContext into a class field (to write JUnit tests). I tried some documented ways:

使用 javax.ws.rs.core.SecurityContext 我得到 NullPointerException ，因为 securityContext 始终是 null 。

With javax.ws.rs.core.SecurityContext I get a NullPointerException, because the securityContext is always null.

@Path("/myresource")
public class MyResoure {

    @Context
    private javax.ws.rs.core.SecurityContext securityContext;

    @Get
    public String getUserName() {
        return securityContext.getUserPrincipal().getName();
    }
}

使用 org.apache。 cxf.security.SecurityContext （参见）我得到 NullPointerException ，因为 securityContext.getUserPrincipal（）总是 null 。

With org.apache.cxf.security.SecurityContext (see Apache CXF documentation) I get a NullPointerException, because the securityContext.getUserPrincipal() is always null.

@Path("/myresource")
public class MyResoure {

    @Context
    private org.apache.cxf.security.SecurityContext securityContext;

    @Get
    public String getUserName() {
        return securityContext.getUserPrincipal().getName();
    }
}

使用 org.apache。 cxf.jaxrs.ext.MessageContext （参见）我得到 NullPointerException ，因为 messageContext.getSecurityContext（）。getUserPrincipal （）总是 null 。

With org.apache.cxf.jaxrs.ext.MessageContext (see Apache CXF documentation) I get a NullPointerException, because the messageContext.getSecurityContext().getUserPrincipal() is always null.

@Path("/myresource")
public class MyResoure {

    @Context
    private org.apache.cxf.jaxrs.ext.MessageContext messageContext;

    @Get
    public String getUserName() {
        return messageContext.getSecurityContext().getUserPrincipal().getName();
    }
}

使用 javax.servlet。 http.HttpServletRequest 我得到 NullPointerException ，因为 httpServletRequest.getUserPrincipal（）总是空。

With javax.servlet.http.HttpServletRequest I get a NullPointerException, because the httpServletRequest.getUserPrincipal() is always null.

@Path("/myresource")
public class MyResoure {

    @Context
    private javax.servlet.http.HttpServletRequest httpServletRequest;

    @Get
    public String getUserName() {
        return httpServletRequest.getUserPrincipal().getName();
    }

推荐答案

获取用户名

• javax.ws.rs.core.SecurityContext ，


• org.apache.cxf.security.SecurityContext ，


• org.apache。 cxf.jaxrs.ext.MessageContext 或


• javax.servlet.http.HttpServletRequest

• javax.ws.rs.core.SecurityContext,
• org.apache.cxf.security.SecurityContext,
• org.apache.cxf.jaxrs.ext.MessageContext or
• javax.servlet.http.HttpServletRequest

我必须将 SecurityContextHolderAwareRequestFilter 添加到我的 springSecurityFilterChain 。

弹簧配置：

<bean id="springSecurityFilterChain" class="org.springframework.security.web.FilterChainProxy">
    <security:filter-chain-map path-type="ant">
        <security:filter-chain pattern="/**" filters="securityContextPersistenceFilter,authenticationProcessingFilter,securityContextHolderAwareRequestFilter,anonymousProcessingFilter,exceptionTranslationFilter,filterSecurityInterceptor" />
    </security:filter-chain-map>
</bean>

使用安全命名空间配置或默认添加过滤器，参见：

With Security Namespace Configuration or Java Configuration the filter is added by default, see Spring Security documentation:

这篇关于使用Apache CXF 2.4 JAX-RS和Spring Security 3.2获取用户名的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！