问题描述
根据 API文档，您可以搜索"sharedWithMe"以与被破坏"相同的方式:
According to the API documentation you can search on 'sharedWithMe' in the same way as 'trashed':
trashed boolean =, != Whether the file is in the trash or not.
sharedWithMe boolean =, != Files that have been shared with the authorized user.
已删除"，未删除"和"trashed = false"之类的查询均按预期工作."sharedWithMe"也可以使用.
Queries like "trashed", "not trashed" and "trashed=false" all work as expected. Also "sharedWithMe" works.
但是什么是行不通的是"not sharedWithMe"或"sharedWithMe = false".正确的语法是什么，或者这是个错误?
However whats does not work is "not sharedWithMe" or "sharedWithMe=false". What is the right syntax or is this a bug?
示例:q = not + sharedWithMe
Example: q=not+sharedWithMe
错误:
"domain": "global",
"reason": "invalid",
"message": "Invalid Value",
"locationType": "parameter",
"location": "q"
推荐答案
我也认为此问题是Google驱动器API实现中的错误.
I also believe this problem is a bug in the google drive API implementation.
我正在通过使用"sharedWithMeTime"解决此问题(在python中)从每个列表请求中获取的属性.在我取回所有项目(无论是否与sharedWithMe)之后，然后，我测试每个项目中是否存在sharedWithMeTime属性.如果不是，则该项目必须为"not sharedWithMe"，这是我想使用的内容作为查询，但出现了OP描述的错误.
I am working around this problem (in python) by using the "sharedWithMeTime"attribute that I get back from each list request.After I get back all the items (sharedWithMe or not),I then test for whether sharedWithMeTime attribute exists in each item.If not, then the item must be "not sharedWithMe", which is what I wanted to useas the query, but was getting the error described by the OP.
链接到列表请求上的python文档的位置在这里: https://developers.google.com/resources/api-libraries/documentation/drive/v3/python/latest/drive_v3.files.html#list
Link to the python doc on list request is here:https://developers.google.com/resources/api-libraries/documentation/drive/v3/python/latest/drive_v3.files.html#list
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