本文介绍了在汇编器中将十进制转换为二进制的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我在汇编程序中的第一个程序需要帮助.我必须将用户输入的值从十进制转换为二进制.我不知道如何将值显示为小数，下一步该怎么做.谁能一步一步指导我下一步该怎么做.
I need help with my first program in assembler.I have to convert values entered by user from decimal to binary.I have no idea how can I show values as a decimal, and what should I do next.could anyone instruct me step by step what do next.
.model small
.stack 100h`
.data
txt1 db "Enter binary value:" ,10,13, "$"
txt2 db "BIN: " ,10,13, "$"
.code
main proc
mov ax, @data
mov ds, ax
;clear screen
mov ah,0fh
int 10h
mov ah,0
int 10h
;show first text
mov ah, 9
mov dx, offset txt1
int 21h
call Number
main endp
Number proc
mov cx,5
xor bx,bx
read:
mov ah,0
int 16h
cmp al,'0'
jb read
cmp al, '9'
ja read
mov ah,0eh
int 10h
loop read
Number endp
mov ax, 4c00h
int 21h
end main
推荐答案
我认为这对您来说还可以.
I think it will be ok for you.
; Read an integer from the screen and display the int in binary format
; and continue until number is negative.
again: ; For loop
call read_int ; take the integer from screen
cmp eax,0 ; look if number is not negative
JL end: ; if less than zero program ends.
mov ecx,32 ; for loop we set ecx to 32 ; ATTENTION we not specified type. So compiler will get error.
mov ebx,eax ; we will lost our number in eax, so I take it to ebx
START:
xor eax,eax ; eax = 0
SHL ebx,1 ; shift the top bit out of EBX into CF
ADC eax,0 ; EAX = EAX + CF + 0 ADD CARRY FLAG, so eax is zero we add zero. The new eax will exact value of Carry Flag which is out bit.
call print_int ; Then we print the CF which we took the eax.
LOOP start: ; Loop looks ecx if not 0 it goes start.
call print_nl ; For next number we print a new line
JMP again: ; For take new number
END: ; End of the program.
setc al 也可以代替 adc eax，0 ，并且在某些CPU上效率更高.
setc al would also work instead of adc eax,0, and be more efficient on some CPUs.
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