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问题描述

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使用以下代码,如果没有给出文件参数,则会抛出第9行的紧急情况 panic:runtime error:index out of range as expected。

With the following code, if no file argument is given, a panic is thrown for line 9 panic: runtime error: index out of range as expected.

我如何抓住这个恐慌,直接传递给它时处理它( os.Args [1] )导致恐慌?很像PHP中的try / catch或者在Python中尝试/除外。

How can I 'catch' this panic and handle it when directly when passing something to it (os.Args[1]) that causes the panic? Much like try/catch in PHP or try/except in Python.

我在StackOverflow上搜索了一下,但是我没有找到任何答案。

I've had a search here on StackOverflow but I've not found anything that answers this as such.

package main

import (
    "fmt"
    "os"
)

func main() {
    file, err := os.Open(os.Args[1])
    if err != nil {
        fmt.Println("Could not open file")
    }
    fmt.Printf("%s", file)
}


推荐答案

Go不是python,你应该在使用它之前正确检查args:

Go is not python, you should properly check for args before you use it:

func main() {
    if len(os.Args) != 2 {
         fmt.Printf("usage: %s [filename]\n", os.Args[0])
         os.Exit(1)
    }
    file, err := os.Open(os.Args[1])
    if err != nil {
        log.Fatal(err)
    }
    fmt.Printf("%s", file)
}

这篇关于在高隆赶上恐慌的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

1403页,肝出来的..

09-07 02:56