什么库可用于解析c ++提取类型信息

问题描述

限时删除！！

我正在寻找一种方法来解析c ++代码来检索一些关于类的基本信息。我实际上不需要来自代码本身的很多信息，但我需要它来处理宏和模板。总之，我想提取代码的结构，你会在UML图中显示什么。

对于每个类/ struct / union / enum / typedef在代码库中，我需要的（处理模板和宏后）是：

• 他们的名字


• 它们所在的命名空间


• （类型名称，字段名称和访问限制，例如private / mutable / etc）中包含的字段




• 声明文件


• 行号/列号
  实际的指令在代码中与我的目的无关。
  
  
  

  我预计很多人说我应该使用正则表达式（或甚至Flex和Bison），但这些都不是真的有效，因为我需要预处理器和模板东西正确处理。

  解决方案

  听起来像一个工作与您选择的c ++ xml库或xml友好的脚本语言相结合。

  
  

  I'm looking for a way to parse c++ code to retrieve some basic information about classes. I don't actually need much information from the code itself, but I do need it to handle things like macros and templates. In short, I want to extract the "structure" of the code, what you would show in a UML diagram.

  For each class/struct/union/enum/typedef in the code base, all I need (after templates & macros have been handled) is:

  • Their name
  • The namespace in which they live
  • The fields contained within (name of type, name of field and access restrictions, such as private/mutable/etc)
  • Functions contained within (return type, name, parameters)
  • The declaring file
  • Line/column numbers (or byte offset in file) where the definition of this data begins

  The actual instructions in the code are irrelevant for my purposes.

  I'm anticipating a lot of people saying I should just use a regex for this (or even Flex & Bison), but these aren't really valid, as I do need the preprocessor and template stuff handled properly.

  解决方案

  Sounds like a job for gcc-xml in combination with the c++ xml-library or xml-friendly scripting language of your choice.

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