操作 | 函数 | 使用方法 | 备注 |
索引 | index | in: example.index(‘creative’) --- 1 in:example[1,] --- [’creative’, [’京东’，996]] | |
赋值 | in: example[1] = [‘commonplace’] --- [1, ‘commonplace’, [’京东’，996]] in: example[2,] = [[‘国企’,855],[‘阿里’，996],[‘博士生’,007]] | ||
删除 | clear pop 索引赋空值 | in: example.clear --- [] in: example.pop() --- [’京东’，996]( example== [1, ’creative’]) in: example[1] = [] --- [1, [’京东’，996]] | clear：就地清空列表的内容 pop : 从列表中删除一个元素，并返回这一元素 |
插入 | insert 索引赋值 | in: example.insert(1,’ commonplace’) --- [1, ’ commonplace’,’creative’, [’京东’，996]] in: example[1:1]=[ ’ anyway’] --- [1, ’ anyway’ ,’creative’, [’京东’，996]] | |
扩展与拼接 | extend append | a = [1,2,3];b= [4,5,6] in: a.extend(b) ---- [1,2,3,4,5,6] in: a.append(7) --- [1,2,3,7] in: a+b [1,2,3,4,5,6](但是，a未改变) | |
复制 | copy | ex = example ex[3] = [‘奋斗==全勤投入？’] in： example --- [1, ’creative’, [’京东’，996]，‘奋斗==全勤投入？] in: ex= example.copy() ex[3] = [‘奋斗==全勤投入？’] in： example --- [1, ’creative’, [’京东’，996]] | “=”，传递位置（指针） copy:只复制元素 |
计数 | count | in: [‘stay’,’hungrey’,’stay’,’foolish’].count(‘stay’) --- 2 | |
排序 | sort sorted | x=[4,6,2,1,7,9] x.sort() in: x --- [1,2,4,7,9] in: y=sorted(x), x --- [1,2,4,7,9], [4,6,2,1,7,9] | sort用于对列表就地排序； sorted不改变原来类别的元素的顺序 |