本文介绍了如何make_shared派生类?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我想对派生类使用make_shared<T>函数，如下所示
I want to use the make_shared<T> function with a derived class, like below
class Base {
public:
typedef std::shared_ptr<Base> Ptr;
};
class Derived : public Base {};
Base::Ptr myPtr = std::make_shared(/* Derived() */ );
如何告诉make_shared构建这样的对象?
How can I tell make_shared to build such an object?
我想避免经典
Base::Ptr ptr = Base::Ptr(new Derived());
要在make_shared函数中使用单个alloc.
To make use of the single alloc in the make_shared function.
推荐答案
std::shared_ptr具有可以从shared_ptr<Derived>生成shared_ptr<Base>的转换构造函数，因此以下应该起作用:
std::shared_ptr has a converting constructor that can make a shared_ptr<Base> from a shared_ptr<Derived>, so the following should work:
#include <memory>
class Base {
public:
typedef std::shared_ptr<Base> Ptr;
};
class Derived : public Base {};
int main() {
Base::Ptr myPtr = std::make_shared<Derived>();
}
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