问题描述
输入图像描述hereOk，我刚开始学习python，我无法弄清楚为什么我的IF / Else语句在输入Else后仍然出现此错误：SyntaxError：unindent与任何外部缩进级别不匹配 。这是我的代码
如果x> 1000：
print（'3'）
else：
enter image description hereOk, I am just starting to learn python, and I can't figure out why my IF/Else statement keeps getting this error after I enter Else: "SyntaxError: unindent does not match any outer indentation level". Here is my code if x>1000: print('3') else:
SyntaxError：SyntaxError：unindent does不匹配任何外部缩进级别
SyntaxError:SyntaxError: unindent does not match any outer indentation level
以下是错误（以下链接）
以下是解决方案：kind-af看起来很有趣，但即使If最初在第4列python将其注册为第0列，所以我不得不把我的其他：放在第0列（即使它看起来不对齐。感谢每一位帮助!!
Here is the error (link below)ErrorHere was the solution: kind-af funny looking, but even though If was initially on column 4 python registered it as column 0, so I had to put my else: on column 0 (even though it didn't look aligned. THANKS EVERYBODY FOR THE HELP!!Solution
推荐答案
啊，IDLE。你试过把它输入shell，对吗？所以看起来像是
Ah, IDLE. You have tried to enter this into shell, right? So the thing looks like
>>> if x > 1000:
print(3)
else:
对吗？重点是，&g计算缩进时t;>> 不计算。事实上，就IDLE而言，if和else在同一列中不是。 :-( [它看到的缩进是0,8,4。]你必须启动 else：完全冲洗到左边距。
right? The point is, >>> doesn't count when calculating indents. So in fact if and else are not in the same column as far as IDLE is concerned. :-( [The indents it sees are 0, 8, 4.] You have to start the else: flush completely to the left margin.
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