用Spring安全性Javaconfig进行基本和基于表单的身份

用Spring安全性Javaconfig进行基本和基于表单的身份

本文介绍了使用Spring安全性Javaconfig进行基本和基于表单的身份验证的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

限时删除!!

我正在尝试为不同的网址模式定义两种不同的安全配置,其中一种使用表单登录,另一种使用api的基本身份验证。

I'm trying to define two different security configurations for different url patterns, one of them using form login and another one using basic authentication for an api.

我正在寻找的解决方案类似于此处解释的解决方案但我想使用java配置。

The solution I'm looking for is similar to the one explained here http://meera-subbarao.blogspot.co.uk/2010/11/spring-security-combining-basic-and.html but I would like to do it using java config.

提前致谢。

这是我目前的配置:

@Configuration
@EnableWebSecurity
public class AppSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private UserService userService;

    @Override
    protected void registerAuthentication(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userService);
    }

    @Override
    public void configure(WebSecurity web) throws Exception {
        // Ignore any request that starts with "/resources/".
        web.ignoring().antMatchers("/resources/**");
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.authorizeUrls().antMatchers("/", "/index", "/user/**", "/about").permitAll()
        .antMatchers("/admin/**").hasRole("ADMIN")
        .anyRequest().authenticated()
        .and().formLogin()
        .loginUrl("/login")
        .failureUrl("/login-error")
        .loginProcessingUrl("/security_check")
        .usernameParameter("j_username").passwordParameter("j_password")
        .permitAll();

        http.logout().logoutUrl("/logout");
        http.rememberMe().rememberMeServices(rememberMeServices()).key("password");
    }

    @Bean
    public RememberMeServices rememberMeServices() {
        TokenBasedRememberMeServices rememberMeServices = new TokenBasedRememberMeServices("password", userService);
        rememberMeServices.setCookieName("cookieName");
        rememberMeServices.setParameter("rememberMe");
        return rememberMeServices;
    }
}


推荐答案

我找到的解决方案是在第一个内部创建另一个扩展WebSecurityConfigurerAdapter的类,如描述

The solution I found was to create another class extending WebSecurityConfigurerAdapter inside the first one, like is described https://github.com/spring-projects/spring-security-javaconfig/blob/master/samples-web.md#sample-multi-http-web-configuration

我的解决方案如下:

@Configuration
@EnableWebSecurity
public class AppSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private UserService userService;

    @Override
    protected void registerAuthentication(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userService);
    }

    @Override
    public void configure(WebSecurity web) throws Exception {
        // Ignore any request that starts with "/resources/".
        web.ignoring().antMatchers("/resources/**");
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.authorizeUrls().antMatchers("/", "/index", "/user/**", "/about").permitAll()
            .antMatchers("/admin/**").hasRole("ADMIN")
            .anyRequest().authenticated()
            .and().formLogin()
            .loginUrl("/login")
            .failureUrl("/login-error")
            .loginProcessingUrl("/security_check")
            .usernameParameter("j_username").passwordParameter("j_password")
            .permitAll();

        http.logout().logoutUrl("/logout");
        http.rememberMe().rememberMeServices(rememberMeServices()).key("password");
    }

    @Bean
    public RememberMeServices rememberMeServices() {
        TokenBasedRememberMeServices rememberMeServices = new TokenBasedRememberMeServices("password", userService);
        rememberMeServices.setCookieName("cookieName");
        rememberMeServices.setParameter("rememberMe");
        return rememberMeServices;
    }

    @Configuration
    @Order(1)
    public static class ApiWebSecurityConfigurationAdapter extends WebSecurityConfigurerAdapter {

        @Override
        protected void registerAuthentication(AuthenticationManagerBuilder auth) throws Exception {
            auth.inMemoryAuthentication().withUser("api").password("pass").roles("API");
        }

        protected void configure(HttpSecurity http) throws Exception {
            http.authorizeUrls()
                .antMatchers("/api/**").hasRole("API")
                .and()
                .httpBasic();
        }
    }
}

这篇关于使用Spring安全性Javaconfig进行基本和基于表单的身份验证的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

1403页,肝出来的..

09-07 01:50