简化CTE字符串串联？ | 简化CTE字符串串联

本文介绍了简化CTE字符串串联？的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有以下代码列表

Code Meaning
1    Single
2    Married/Separate
3    Divorced
4    Widowed
8    Not Applicable
99   Not known

我正在尝试使用CTE将它们展平为一行。我有一个使用RowNumber函数执行此操作的CTE解决方案。

I am trying to flatten these into a single row using a CTE. I have a CTE solution which uses RowNumber function to do this.

WITH Flattened (JoinItem, CodeMeaning) AS
(
    SELECT 1 AS JoinItem, CAST('' AS VARCHAR(255))
    UNION ALL
    SELECT f.JoinItem+1, CAST(f.CodeMeaning + ',' + c.CodeMeaning AS VARCHAR(255))
    FROM
    (
        SELECT JoinItem = ROW_NUMBER() OVER (ORDER BY Code),c.Code + ' - ' + c.Meaning AS CodeMeaning
        FROM Codes c
    ) c
    INNER JOIN Flattened f
    ON f.JoinItem=c.JoinItem
)
SELECT TOP 1 JoinItem,  CodeMeaning
FROM Flattened
ORDER BY JoinItem DESC

但是，我想知道是否可以不使用RowNumber函数，但仍使用CTE。所以我有以下内容-我认为更简单的内容-Sql

However, I'm wondering if I can do it without using the RowNumber function but still using a CTE. So I have the following - what I view as simpler - Sql

WITH Flattened (JoinItem, CodeMeaning) AS
(
    SELECT 1 AS JoinItem, CAST('' AS VARCHAR(255))
    UNION ALL
    SELECT c.JoinItem, CAST(f.CodeMeaning + ',' + c.CodeMeaning AS VARCHAR(255))
    FROM
    (
        SELECT 1 AS JoinItem,c.Code + ' - ' + c.Meaning AS CodeMeaning
        FROM Codes c
    ) c
    INNER JOIN Flattened f
    ON f.JoinItem=c.JoinItem
)
SELECT JoinItem, odeMeaning
FROM Flattened

现在，它可以最大限度地提高递归并生成笛卡尔联接之类的东西-如果还不算差的话！

Now it is max-ing out on recursion and generating something like a cartesian join - if not worse!

我正在尝试使用固定的 JoinItem每次尝试将其加入锚记录中

I'm looking to try and get it to join to the anchor record each time using a fixed "JoinItem"

因此，任何指向我要去哪里的指针都将

So any pointers to where I am going wrong would be helpful if there is a solution.

编辑

推荐答案

假设这是SQL Server，您是否考虑过这样的事情：

Assuming this is SQL Server, have you considered something like this:

select stuff((select ',' + c.code + '-' + c.Meaning
              from codes c
              order by code
              for xml path ('')
             ), 1, 1, '')

编辑：

要使用CTE进行此操作，请先定义序号，然后进行展平：

To do this with a CTE, define the sequential numbers first and then do the flattening:

with c as (
      select row_number() over (order by code) as seqnum, c.code + '-' + c.meaning as CodeMeaning
      from codes c
     ),
     flattened as (
      select CodeMeaning as CodeMeaning
      from c
      where rownum = 1
      union all
      select f.CodeMeaning + ',' + c.CodeMeaning
      from c join
           flattened f
           on c.seqnum = f.seqnum + 1
     )
select *
from flattened;

如果列表太长，则可能必须增加默认递归级别。

You might have to increase the default recursion level if your list is too long.

这篇关于简化CTE字符串串联？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！

1403页，肝出来的..