首先需要建一个实体类 Person.java 来对应json
需要注意的是实体类中的变量名必须和json传过来的key值完全一样(大小写)
public class Person {
private String name;
private int age;
private String city; public Person(String name, int age, String city){
this.name = name;
this.age = age;
this.city = city;
} public Person(){} public void setName(String name) {
this.name = name;
} public String getName() {
return name;
} public void setAge(int age) {
this.age = age;
} public int getAge() {
return age;
} public void setCity(String city) {
this.city = city;
} public String getCity() {
return city;
}
}
然后这是编码和解码的具体实现
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log; import com.google.gson.Gson;
import com.google.gson.reflect.TypeToken; import java.lang.reflect.Type;
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List; public class MainActivity extends AppCompatActivity { @Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main); List<Person> list = new ArrayList<Person>();
Person person = new Person("Thh", 23, "CHENGDU");
list.add(person);
person = new Person("CBB", 22, "CHENGDU");
list.add(person);
person = new Person("CMT", 18, "TIANJIN");
list.add(person); Gson gson = new Gson(); Log.e("ABC", "" + gson.toJson(list)); Person person1 = new Person();
Gson gson1 = new Gson(); String s=gson.toJson(list);
Type lt=new TypeToken<List<Person>>(){}.getType();//获取一个泛型的数据类型
List<Person> l=gson1.fromJson(s,lt);
for(Person p1:l){
Log.e("ABC",p1.getName() + " " + p1.getAge() + " " + p1.getCity());
}
}
}
Logcat中显示结果:
10-22 01:22:01.444 16669-16669/? E/ABC: [{"age":23,"city":"CHENGDU","name":"Thh"},{"age":22,"city":"CHENGDU","name":"CBB"},{"age":18,"city":"TIANJIN","name":"CMT"}]
10-22 01:22:01.448 16669-16669/? E/ABC: Thh 23 CHENGDU
10-22 01:22:01.448 16669-16669/? E/ABC: CBB 22 CHENGDU
10-22 01:22:01.449 16669-16669/? E/ABC: CMT 18 TIANJIN