使用艺术家动画每秒拍摄快照 | 使用艺术家动画每秒拍摄快照

本文介绍了使用艺术家动画每秒拍摄快照的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我使用此功能:

def Plot(data):

    plt.colormaps()
    n=sc.shape(data)[2]
    ims=[]
    for i in range(n):
        mydata=data[:,:,i]
        im=plt.imshow(mydata,cmap=plt.get_cmap('jet'))
        ims.append([im])
    return ims

并这样称呼它:

fig=plt.gcf()
ani=ArtistAnimation(fig,result,interval=10,repeat=False)
plt.show()

例如，我想问一下是否可以每 1 秒拍摄一次情节(动画)的快照.

I want to ask if it possible to take snapshots of the plot(animation) for every 1 second for example.

(我使用matplotlib)

(I use matplotlib)

推荐答案

您可以子类化 ArtistAnimation 并覆盖 _step - 方法，例如:

You could subclass ArtistAnimation and overwrite the _step - method, e.g.:

class SnapShotAnimation(ArtistAnimation):
    def __init__(self, fig, artists, snapshot_delay, *args, **kwargs):
        self._snapshot_delay = snapshot_delay
        self._time_to_snapshot = snapshot_delay
        ArtistAnimation.__init__(self, fig, artists, *args, **kwargs)

    def _step(self, *args):
        if self._time_to_snapshot <= 0:
            do_snapshot()
            self._time_to_snapshot = self._snap_shot_delay #reset timer
        else:
            self._time_to_snapshot -= self._interval
        ArtistAnimation._step(*args) #ancestor method maybe better at start

    def do_snapshot(self):
        """Your actual snapshot code comes here - basically saving to a output"""
        fname = 'snapshot.png'
        self._fig.savefig(fname)

添加:

snapshot_delay = 1000 # time in ms

改变:

ani=SnapShotAnimation(fig,result,snapshot_delay, interval=10,repeat=False)

在您的示例源中.

为了更好地了解做什么和如何做，我建议查看 matplotlib 来源.

For better understanding what and how to do, i would recommend to take a look into the matplotlib sources.

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