通过 Selenium 进行类人鼠标移动

问题描述

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故事:

解决验证码的方法之一，如 Google ReCaptcha，是尝试模仿人类鼠标动作:移动、悬停和点击.

One of the approaches to solve captchas, like Google ReCaptcha, is to try to imitate the human mouse actions: movements, hovering and clicks.

一些用户报告将鼠标移动为B-spline 曲线 为他们工作.

Some users reported that making mouse moves as B-spline curves worked for them.

问题:

如何通过 Selenium 按照 B 样条轨迹将鼠标移动到特定元素?

How to move the mouse to a particular element following the B-spline trajectory via Selenium?

请注意，常规的 browser.actions().mouseMove(elm).perform(); 会直接跳"到元素，而且速度太快.我的理解是减慢运动速度，按照B样条轨迹的数学模型平滑地跳"到点.

Note that the regular browser.actions().mouseMove(elm).perform(); would "jump" to the element straight and far too quickly. My understanding is that it is a matter of slowing down the movement speed, "jumping" from point to point smoothly following the mathematical model for the B-spline trajectory.

推荐答案

您可以使用 scipy.interpolate 来插入 B 样条曲线，就像您在此 问题.

You can use scipy.interpolate to interpolate B-spline curves like you can see in this question.

在这里，我将使用 B-spline 示例之一来获取 x 和 y 的值:

Here I'll use one of the B-spline examples to get values to x and y:

import numpy as np
import scipy.interpolate as si

# Curve base:
points = [[0, 0], [0, 2], [2, 3], [4, 0], [6, 3], [8, 2], [8, 0]];
points = np.array(points)

x = points[:,0]
y = points[:,1]


t = range(len(points))
ipl_t = np.linspace(0.0, len(points) - 1, 100)

x_tup = si.splrep(t, x, k=3)
y_tup = si.splrep(t, y, k=3)

x_list = list(x_tup)
xl = x.tolist()
x_list[1] = xl + [0.0, 0.0, 0.0, 0.0]

y_list = list(y_tup)
yl = y.tolist()
y_list[1] = yl + [0.0, 0.0, 0.0, 0.0]

x_i = si.splev(ipl_t, x_list) # x interpolate values
y_i = si.splev(ipl_t, y_list) # y interpolate values

使用x 和y 的值，您可以使用ActionChains 移动鼠标光标:

With values of x and y, you can move the mouse cursor with ActionChains:

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains

url = "https://codepen.io/falldowngoboone/pen/PwzPYv"
driver = webdriver.Chrome(executable_path="/home/selenium/chromedriver2.25")
driver.get(url)

action =  ActionChains(driver);

startElement = driver.find_element_by_id('drawer')

# First, go to your start point or Element:
action.move_to_element(startElement);
action.perform();

for mouse_x, mouse_y in zip(x_i, y_i):
    action.move_by_offset(mouse_x,mouse_y);
    action.perform();
    print(mouse_x, mouse_y)

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