问题描述
我正在尝试拆分一个 ArrayList 并使用 Apache Camel 将每个元素写入它自己的文件，就像在这个简化的例子中一样:
I´m trying to split an ArrayList and writing each element to it´s own file using Apache Camel like in this simplified example:
from("timer://poll?period=10000").process(new Processor(){
public void process(Exchange exchange){
ArrayList<String> list = new ArrayList<String>();
list.add("one");
list.add("two");
list.add("three");
exchange.getIn().setBody(list, ArrayList.class);
}
}).split(body()).log(body().toString()).to("file:some/dir");
日志打印每个项目，但只有三个"保存到文件中.我做错了什么?
The log prints each item but only "three" is saved to a file. What am I doing wrong?
一月
推荐答案
如果文件已经存在，文件生成器将默认覆盖".
The file producer will by default "override" if a file already exists.
在其文档页面查看 fileExist 选项http://camel.apache.org/file2
See the fileExist option at its documentation pagehttp://camel.apache.org/file2
由于此路由的输入也是一个文件，因此生产者将从输入中继承"文件名.
Since the input to this route is also a file, then the producer will "inherit" the file name from the input.
因此，在您的情况下，如果要将每个拆分的消息保存在新文件中，则需要使用 fileName 选项设置目标文件名
So in your case if you want to save each splitted message in a new file, then you would need to set a target file name, using the fileName option
"file:some/dir?fileName=splitted-${id}"
fileName 选项支持简单和文件语言
The fileName option supports the simple and file language
http://camel.apache.org/simple.html
http://camel.apache.org/file-language.html
这意味着可以动态计算文件名，例如上面的 ${id} 是唯一的消息 ID.
That means the file name can be dynamic computed, such as above, where ${id} is an unique message id.
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