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问题描述

限时删除!!

此处我读过在C ++中的std :: set是通常实现为一个树(红黑一个?),它被排序。



我不明白, 按规范设置的迭代顺序始终为升序?

解决方案

根据C ++标准,这是一个常见的实现细节,在 std :: set 中的元素的迭代按照 std :: less 或由可选的比较谓词模板参数。



(另外根据C ++标准,插入,查找和删除最多花费O(lg n ,所以平衡的搜索树目前是 std :: set 的唯一可行的实现选择,即使红黑树的使用没有被标准强制。)


Here http://www.cplusplus.com/reference/stl/set/ I read that std::set in C++ is "typically" implemented as a tree (red-black one?) and it is sorted.

I could not understand, does it mean that by specification iteration order of set is always ascending? Or is it only "usual implementation detail" and sometimes, some library/compiler may violate this convention?

解决方案

Per the C++ standard, iteration over the elements in an std::set proceeds in sorted order as determined by std::less or by the optional comparison predicate template argument.

(Also per the C++ standard, insertion, lookup and deletion take at most O(lg n) time, so balanced search trees are currently the only viable implementation choice for std::set, even though the use of red-black trees is not mandated by the standard.)

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09-06 22:57