问题描述
对于Ex-
如果用户在文本框中输入
bookno-101本总本-2
bookno - 101 totalbook - 2
receiptno-500总记录-2
receiptno - 500 totalrec - 2
优惠券-700总额-2
coupon - 700 totalcoup - 2
然后输出如下表所示.
在此表中，优惠券编号始终是唯一的.收据编号两次出现，每张收据都分配了两张优惠券.
对于Ex-
图书收据优惠券
101500-700
101 500 - 700
101500-701
101 500 - 701
101-501-702
101 - 501 - 702
101-501-703
101 - 501 - 703
102-502-704
102 - 502 - 704
102-502-705
102 - 502 - 705
102-503-706
102 - 503 - 706
102-503-707
102 - 503 - 707
现在是我第二次输入
bookcode = 800book_no2 = 802
bookcode = 800book_no2 = 802
收据代码= 1600Temp_receipt = 1602
receiptcode = 1600Temp_receipt = 1602
优惠券代码= 1800
Temp_coupon = 1802
couponcode = 1800
Temp_coupon = 1802
然后生成如下所示的输出
then generate output like below
图书收据优惠券801 -1601 1801801 -1601 -1802801 -1602 -1803801 -1602 -1804802 -1603 -1805802 -1603 -1806802 -1604 -1807802 -1604 -1808
book receipt coupon801 -1601 1801801 -1601 -1802801 -1602 -1803801 -1602 -1804802 -1603 -1805802 -1603 -1806802 -1604 -1807802 -1604 -1808
我尝试下面的代码，但工作不正常.
i try below code but not working properly.
<?php
if(isset($_POST['save']))
{
$bookcode = $_POST['bookcode'];
$book_no2 = $_POST['book_no2'];
$receiptcode = $_POST['receiptcode'];
$receipt_no = $_POST['receipt_no'];
$couponcode = $_POST['couponcode'];
$coupon = $_POST['coupon'];
$Temp_receipt = $receiptcode + $receipt_no;
$Temp_coupon = $couponcode + $coupon;
for($row1=$bookcode+1;$row1<=$bookcode+$book_no2;$row1++)
{
for($row=$receiptcode+1;$row<=$Temp_receipt;$row++)
{
$query = $database->getRow("SELECT MAX(receipt_no) AS max1 FROM scheme_master;");
if($query['max1']=='')
{
$largestNumber = $receiptcode;
$top = $largestNumber + 1;
}
else
{
$largestNumber = $query['max1'];
$top = $largestNumber + 1;
}
$Pric = "";
$loopCount = 0;
for($row2=$couponcode+1;$row2<=$Temp_coupon;$row2++)
{
$query = $database->getRow("SELECT MAX(coupon) AS max2 FROM scheme_master;");
if($query['max2']=='')
{
$largestcoupon = $couponcode;
$coup = $largestcoupon + 1;
}
else
{
$largestcoupon = $query['max2'];
$coup = $largestcoupon + 1;
}
$value = $loopCount++ + 1;
$code = '- mths';
$Pric=$value.$code;
$insertrow = $database->insertRow("INSERT INTO scheme_master (book_no2,receipt_no,coupon)
VALUES (:book_no2,:receipt_no,:coupon)",
array(':receipt_no'=>$top,':book_no2'=>$row1,':coupon'=>$coup));
}
}
}
$_SESSION['message'] = "Books Created Successfully";
}
?>
我正在得到如下表所示的输出...
图书收据优惠券
101-501 -701
101 - 501 -701
101-502 -702
101 - 502 -702
102-501 -701
102 - 501 -701
102-502 -702
102 - 502 -702
推荐答案
每次使用循环时，它都会重置回输入的值(例如coupon_no)
Each time you use a loop it resets back to the entered value (e.g., coupon_no)
您应使用bookno，couponno和receiptno的值作为起点，并使用totalbook，totalcoup和totalrec的值作为循环标准.随手增加数字:
You should use the values for bookno, couponno and receiptno as starting points and the values for totalbook, totalcoup and totalrec as the loop criteria. Increment the numbers as you go:
<?php
$bookno= $_POST['bookcode'];
$totalbook= $_POST['book_no2'];
$receiptno = $_POST['receiptcode'];
$totalrec= $_POST['receipt_no'];
$couponno= $_POST['couponcode'];
$totalcoup= $_POST['coupon'];
for ($book_counter=1; $book_counter<=$totalbook; $book_counter++)
{
for($rec_counter=1; $rec_counter<=$totalrec; $rec_counter++)
{
for($coup_counter=1; $coup_counter<=$totalcoup; $coup_counter++)
{
$insertrow = $database->insertRow(
"INSERT INTO scheme_master (book_no2,receipt_no,coupon) VALUES (:book_no2,:receipt_no,:coupon)",
array(':receipt_no'=>$receiptno,':book_no2'=>$bookno,':coupon'=>$couponno));
$couponno++;
}
$receiptno++;
}
$bookno++;
}
?>
注意事项(此功能尚未经过测试，但可以让您走上正确的道路)
NB This has not been tested but it should set you on the right path
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