问题描述
我正在使用++:运算符来获取两个集合的集合，但是使用这两种方法获得的结果不一致:
I am using the ++: operator to get a collection of two collections, but the results I get using these two methods are inconsistent:
scala> var r = Array(1, 2)
r: Array[Int] = Array(1, 2)
scala> r ++:= Array(3)
scala> r
res28: Array[Int] = Array(3, 1, 2)
scala> Array(1, 2) ++: Array(3)
res29: Array[Int] = Array(1, 2, 3)
为什么++:和++:=运算符给出不同的结果?++运算符不会出现这种差异.
Why do the ++: and ++:= operators give different results?This kind of difference does not appear with the ++ operator.
我正在使用的Scala版本是2.11.8.
The version of Scala I am using is 2.11.8.
推荐答案
由于它以冒号结尾，因此++:是右关联的.这意味着Array(1, 2) ++: Array(3)等同于Array(3).++:(Array(1, 2)). ++:可以被认为是将左数组的元素添加到右数组的前面."
Since it ends in a colon, ++: is right-associative. This means that Array(1, 2) ++: Array(3) is equivalent to Array(3).++:(Array(1, 2)). ++: can be thought of as "prepend the elements of the left array to the right array."
由于它是右关联的，所以r ++:= Array(3)减少了对r = Array(3) ++: r的影响.当您认为++:的目的是前置的时，这是有道理的.对于任何以冒号结尾的运算符，这种减法都是适用的.
Since it's right-associative, r ++:= Array(3) desugars to r = Array(3) ++: r. This makes sense when you consider that the purpose of ++: is prepending. This desugaring holds true for any operator that ends in a colon.
如果要追加，可以使用++(和++=).
If you want to append, you can use ++ (and ++=).
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