在Node.js退出之前进行清理操作

问题描述

限时删除！！

我想告诉Node.js总是在退出之前总是做某事，无论出于什么原因- + ，异常或任何其他原因.

I want to tell Node.js to always do something just before it exits, for whatever reason — +, an exception, or any other reason.

我尝试过:

process.on('exit', function (){
    console.log('Goodbye!');
});

我开始了该过程，将其杀死，但没有任何反应.我再次启动它，按 + ，仍然没有任何反应...

I started the process, killed it, and nothing happened. I started it again, pressed +, and still nothing happened...

推荐答案

更新:

您可以为process.on('exit')注册一个处理程序，在任何其他情况下(SIGINT或未处理的异常)可以调用process.exit()

UPDATE:

You can register a handler for process.on('exit') and in any other case(SIGINT or unhandled exception) to call process.exit()

process.stdin.resume();//so the program will not close instantly

function exitHandler(options, exitCode) {
    if (options.cleanup) console.log('clean');
    if (exitCode || exitCode === 0) console.log(exitCode);
    if (options.exit) process.exit();
}

//do something when app is closing
process.on('exit', exitHandler.bind(null,{cleanup:true}));

//catches ctrl+c event
process.on('SIGINT', exitHandler.bind(null, {exit:true}));

// catches "kill pid" (for example: nodemon restart)
process.on('SIGUSR1', exitHandler.bind(null, {exit:true}));
process.on('SIGUSR2', exitHandler.bind(null, {exit:true}));

//catches uncaught exceptions
process.on('uncaughtException', exitHandler.bind(null, {exit:true}));

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