从Swift中的Ascii Int转换为Char / String

问题描述

限时删除！！

我正在尝试将ascii字符的整数表示形式转换回字符串。

I'm trying to convert the integer representation of an ascii character back into a string.

string += (char) int;

在Java等其他语言（此处的示例）中，我可以将整数转换为char。 Swift显然不知道这些，我猜测使用所有强大的NSString以某种方式将能够做到这一点。

In other languages like Java (the example here) I can just cast the integer into a char. Swift obviously does not know these and I'm guessing using the all powerful NSString somehow will be able to do the trick.

推荐答案

它可能不像Java一样干净，但你可以这样做：

It may not be as clean as Java, but you can do it like this:

var string = ""
string.append(Character(UnicodeScalar(50)))

如果您愿意，您还可以修改语法以使其更相似：

You can also modify the syntax to look more similar if you like:

//extend Character so it can created from an int literal
extension Character: IntegerLiteralConvertible {
    public static func convertFromIntegerLiteral(value: IntegerLiteralType) -> Character {
        return Character(UnicodeScalar(value))
    }
}

//append a character to string with += operator
func += (inout left: String, right: Character) {
    left.append(right)
}

var string = ""
string += (50 as Character)

或者使用dasblinkenlight的方法：

Or using dasblinkenlight's method:

func += (inout left: String, right: Int) {
    left += "\(UnicodeScalar(right))"
}
var string = ""
string += 50

这篇关于从Swift中的Ascii Int转换为Char / String的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！

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