问题描述
是否可以在with_item
语句中为每个项目设置tags
?
Is it possible to set tags
per each item in a with_item
statement?
假设我有一个任务:
- name: ensure required packages are installed
apt: pkg={{ item }} state=present
with_items:
- package_1
- package_2
sudo: yes
当用户在命令行中定义--tags "second"
时,我只希望安装package_2
.
When user defines --tags "second"
in a command line I want only package_2
to be installed.
是否可以使用tags
表达式或其他任何方式来获得所需的行为?
Is it possible to do with tags
expression or any other ways to get desired behaviour?
推荐答案
我认为这是不可能的. yum模块(我想它类似于apt)状态:
I don't believe this is possible. The yum module (which I imagine is similar to apt) states:
您需要在package_2任务上将命令分成两个单独的带有"second"标签的打包任务.
You would need to split the command into two seperate package tasks with tag "second" on the package_2 task.
编辑
请参见下面的示例,该示例使用when条件迭代集合,以便仅打印带有正确标签的第二个项目.希望这会有所帮助.
See below of an example of iterating a collection with a when condition so it only prints the second item with the correct tag. Hopefully this helps.
---
- name: Only run certain items in a list
hosts: localhost
tasks:
- name: Echo items based on a tag condition
shell: echo {{item.cmd}}
with_items:
- {cmd: 'package_1', tag: 'first'}
- {cmd: 'package_2', tag: 'second'}
when: item.tag == "second"
这篇关于Ansible:在循环中为每个项目设置标签的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!