问题描述
是否可以在 with_item
语句中为每个项目设置 tags
?
Is it possible to set tags
per each item in a with_item
statement?
假设我有一个任务:
- name: ensure required packages are installed
apt: pkg={{ item }} state=present
with_items:
- package_1
- package_2
sudo: yes
当用户在命令行中定义 --tags "second"
时,我只想安装 package_2
.
When user defines --tags "second"
in a command line I want only package_2
to be installed.
是否可以使用 tags
表达式或任何其他方式来获得所需的行为?
Is it possible to do with tags
expression or any other ways to get desired behaviour?
推荐答案
我不相信这是可能的.yum 模块(我认为它类似于 apt)状态:
I don't believe this is possible. The yum module (which I imagine is similar to apt) states:
当与 playbook 中的包名循环一起使用时,ansible优化对 yum 模块的调用.而不是调用模块每次循环使用一个包时,ansible 调用模块一次,包含循环中的所有包名.
您需要将命令拆分为两个单独的包任务,并在 package_2 任务上标记second".
You would need to split the command into two seperate package tasks with tag "second" on the package_2 task.
编辑
请参阅下面的示例,该示例使用 when 条件迭代集合,因此它仅打印具有正确标签的第二项.希望这会有所帮助.
See below of an example of iterating a collection with a when condition so it only prints the second item with the correct tag. Hopefully this helps.
---
- name: Only run certain items in a list
hosts: localhost
tasks:
- name: Echo items based on a tag condition
shell: echo {{item.cmd}}
with_items:
- {cmd: 'package_1', tag: 'first'}
- {cmd: 'package_2', tag: 'second'}
when: item.tag == "second"
这篇关于Ansible:为循环中的每个项目设置标签的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!