repeat内动态加载模板

repeat内动态加载模板

本文介绍了在ng-repeat内动态加载模板的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

限时删除!!

我试图在 ng-repeat 内动态加载模板:

 < UL> 
< li ng-repeat =实体中的道具>
< div ng-include src =prop.template>< / div>
< / li>
< / ul>

prop.template 等于模板,例如的partials /形式/ text.html 。上面的代码会产生以下错误:
$ b

 错误:达到了10次$ digest()迭代。中止! 
Watchers在最近5次迭代中触发:[[prop.template; newVal:\partials / form / text.html\; oldVal:undefined,prop.template; newVal:\ partials / form / text.html\; oldVal:undefined....(等等)

如何从 prop.template 获取模板的URL,并将该文件中的HTML插入到 ng-repeat

解决方案

问题不在于此处的代码,它应该是完美的工作。请参阅此处的工作示例:



问题是您的 ngRepeat ing数组中的元素数量可能太多,或者您的数组模板或模板包括做太多东西,提高角度的无限循环保护。我投了第二个$ / b $ b $

I am trying to dynamically load a template within an ng-repeat:

<ul>
    <li ng-repeat="prop in entity" >
        <div ng-include src="prop.template"></div>
    </li>
</ul>

prop.template equals the URL of the template, e.g. 'partials/form/text.html'. The above code produces the following error:

Error: 10 $digest() iterations reached. Aborting!
Watchers fired in the last 5 iterations: [["prop.template; newVal: \"partials/form/text.html\"; oldVal: undefined","prop.template; newVal: \"partials/form/text.html\"; oldVal: undefined" .... (and so on)

How do I get the URL of the template from prop.template and insert the HTML from that file into the DOM within ng-repeat?

解决方案

The problem is not about the code here, it should be working perfectly. See the working example here: http://jsfiddle.net/fmjf8/2/

The problem is either you may have too many elements in your ngRepeating array OR the template your array, or the template you are including is doing too many stuff, raising angular's infinite loop protection. I vote for the second

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1403页,肝出来的..

09-06 21:15