问题描述
我目前正在使用带有chart.js的折线图,并且有一个标签集,看起来像 [2015年1月,2015年2月,2015年3月,2015年4月 ,2015年5月,2015年6月]
。我希望相关标签显示在图表的工具提示中,但只希望每个交替的标签显示在图表的x轴上,以防止拥挤。是否有一种方法可以实现这个?
我目前用替换我的数组中的每个第二个值,但是虽然从x轴删除拥挤,
只需扩展折线图,替换你所需要的xLabel,
Chart.types.Line.extend({
name:LineAlt,
initialize:function(data){
Chart.types.Line.prototype.initialize.apply(this,arguments);
var xLabels = this.scale.xLabels
xLabels.forEach function(label,i){
if(i%2 == 1)
xLabels [i] ='';
})
}
}
var lineChartData = {
labels:[January,February,March,April,May,June,July ,August,September,October,November,December],
datasets:[
{
fillColor:#79D1CF,
strokeColor :#79D1CF,
data:[59,80,81,56,55,40,34,43,43,12,65,65]
}
]
};
var ctx = document.getElementById(myChart)。getContext(2d);
var myLine = new Chart(ctx).LineAlt(lineChartData);
Fiddle -
I currently am using a line chart with chart.js, and have a label set that looks like this ["January 2015", "February 2015", "March 2015", "April 2015", "May 2015", "June 2015"]
. I want the relevant label to show up in the tooltip for the chart, but only want every alternating label to show up on the x axis of the chart to prevent crowding. Is there a way I can achieve this ?
I am currently replacing every second value from my array with "", but while that removes the crowding from my x axis, it does not meet my requirement to show the label in the tooltip.
Just extend the line chart and replace the xLabels you don't want after your initialization
Chart.types.Line.extend({
name: "LineAlt",
initialize: function (data) {
Chart.types.Line.prototype.initialize.apply(this, arguments);
var xLabels = this.scale.xLabels
xLabels.forEach(function (label, i) {
if (i % 2 == 1)
xLabels[i] = '';
})
}
});
var lineChartData = {
labels: ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"],
datasets: [
{
fillColor: "#79D1CF",
strokeColor: "#79D1CF",
data: [59, 80, 81, 56, 55, 40, 34, 43, 43, 12, 65, 65]
}
]
};
var ctx = document.getElementById("myChart").getContext("2d");
var myLine = new Chart(ctx).LineAlt(lineChartData);
Fiddle - http://jsfiddle.net/ttz5t3dx/
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