使用RxSwift/RxCocoa订阅UINavigationController后退按钮

问题描述

限时删除！！

我有一个简单的测试项目，其中以UINavigationController作为我的rootViewController.

I have a simple test project with a UINavigationController as my rootViewController.

我按下第一个ViewController，它带有一个+按钮，作为右栏按钮，我订阅它的水龙头以显示一个新的ViewController(与上一个相同).推送功能按我的预期工作.

I push the first ViewController which has a + button as right bar button item, I subscribe to its taps to present a new ViewController (which is identical to the previous one).The push segue works as I expect.

UIKit为我管理后退按钮，我认为是UINavigationController在幕后制造了魔力.

UIKit manages the back button for me and I think it is UINavigationController that makes the magic behind the scene.

现在，我需要做的是订阅后退"按钮，但是我找不到执行该操作的方法.我尝试过

Now, what I need to do is subscribe to the back button, but I can't find how to do this.I have tried with

1. navigationController.navigationBar.backItem?.backBarButtonItem?.rx.tap

navigationController.navigationItem.backBarButtonItem?.rx.tap但它们似乎为零，因此可选链接阻止了订阅.

navigationController.navigationItem.backBarButtonItem?.rx.tapbut they seem to be nil, so the optional chaining prevents subscription.

感谢您的帮助，卢卡-

推荐答案

我认为您最好的选择是在UINavigationController上使用运算符.

I think your best bet here is to use the operator on UINavigationController.

navigationController.rx.willShow将触发.火灾发生时，您可以在最后一分钟进行清理.

navigationController.rx.willShow will trigger whenever a view controller is about to be shown. You can do any last minute clean up when it fires.

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