问题描述
我写一个Android应用程序，用户必须选择的方式和内容，以显示在图表上。这些选项pssed中的两个单选择菜单组（单选按钮），这两者应该是从操作栏访问EX $ P $。
I am writing an Android app where the user must choose how and what to display on a graph. These options are expressed in two single-selection menu groups (radio buttons), both of which should be accessible from the action bar.
第一组工作正常。它在我的动作条XML的结尾是这样说：
The first group works fine. It's added at the end of my ActionBar XML like this:
<group android:checkableBehavior="single" android:showAsAction="never" >
<item android:id="@+id/menu_choice_1" android:title="Choice 1" />
<item android:id="@+id/menu_choice_2" android:title="Choice 2" android:checked="true"/>
</group>
当我添加第二个＆LT;组＆gt; 下面的第一个，但是，这两个合并成一个单一的选择列表。换句话说，从两个列表的选项都呈现在一起，如果我选择属于第一列表中的选项，我不能选择从第二个事情。
When I add a second <group> below the first one, however, the two merge into one single-selection list. In other words, the options from both lists are rendered together and if I choose an option pertaining to the first list, I cannot choose anything from the second.
相反，我想两个单独的列表的单选按钮。我的下一个想法是添加一个按钮的动作条，点击后，将推出的 。但是，当我按一下按钮，我得到一个 IllegalStateException异常，说我MenuPopupHelper不能使用没有锚。
Instead, I want two separate lists of radio buttons. My next idea was to add another button the ActionBar that, when clicked, would launch a pop-up menu. But when I click the button, I get an IllegalStateException, saying that my "MenuPopupHelper cannot be used without an anchor".
下面是我试图弹出菜单code：
Here is my attempted pop-up menu code:
在我的动作条XML：
<item android:id="@+id/menu_openothermenu"
android:title="@string/openothermenustr"
android:showAsAction="always" />
我的新菜单中的XML：
My new menu XML:
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
<group android:checkableBehavior="single">
<item android:id="@+id/menu_2_choice_1" android:title="@string/2_choice_1" />
<item android:id="@+id/menu_2_choice_2" android:title="@string/2_choice_2" android:checked="true"/>
</group>
</menu>
code在我的活动：
Code in my Activity:
@Override
public boolean onOptionsItemSelected(MenuItem item) {
SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
SharedPreferences.Editor editor;
switch (item.getItemId()) {
case R.id.openothermenu:
Menu m = (Menu) findViewById(R.menu.other_menu);
PopupMenu popup = new PopupMenu(this, findViewById(R.menu.main_menu));
popup.setOnMenuItemClickListener(this);
MenuInflater inflater = popup.getMenuInflater();
inflater.inflate(R.menu.other_menu, popup.getMenu());
/* This commented block doesn't work either, and prevents execution
// Restore saved chosen value
int chosen = settings.getInt(MENU_2_PREFS, -1);
switch(chosen)
{
case 1:
m.findItem(R.id.menu_1_choice_1).setChecked(true);
updateVisibleThings();
break;
default:
case 2:
m.findItem(R.id.menu_2_choice_2).setChecked(true);
updateOtherVisibleThings();
break;
}
*/
popup.show();
return true;
default:
return super.onOptionsItemSelected(item);
}
}
@Override
public boolean onMenuItemClick(MenuItem item) {
SharedPreferences settings = getSharedPreferences(PREFS_NAME, 0);
SharedPreferences.Editor editor;
switch(item.getItemId()) {
case R.id.menu_2_choice_1:
if (item.isChecked()) item.setChecked(false);
else item.setChecked(true);
updateVisibleThings();
// save chosen setting
editor = settings.edit();
editor.putInt(MENU_2_PREFS, 1);
editor.commit(); // Commit the edits!
return true;
case R.id.menu_2_choice_2:
if (item.isChecked()) item.setChecked(false);
else item.setChecked(true);
updateOtherVisibleThings();
// save chosen setting
editor = settings.edit();
editor.putInt(MENU_2_PREFS, 2);
editor.commit(); // Commit the edits!
return true;
default:
return true;
}
}
如何创建两套辨认的菜单项，使得两个连接到动作条？
推荐答案
我发现了一个优雅的方式来解决这个问题，这是不幸的是没有的文件中。添加以下code到你的动作条菜单中的XML：
I found an elegant way to solve this that was unfortunately not in the documentation. Add the following code to your ActionBar menu XML:
<item android:id="@+id/menu_openothermenu"
android:title="@string/openothermenustr"
android:showAsAction="always">
<menu>
<group android:checkableBehavior="single">
<item android:id="@+id/menu_2_choice_1" android:title="@string/2_choice_1" android:showAsAction="never" />
<item android:id="@+id/menu_2_choice_2" android:title="@string/2_choice_2" android:showAsAction="never" android:checked="true" />
</group>
</menu>
</item>
没有额外的处理程序code或弹出菜单的实现是必要出现这样的菜单。
No extra handler code or popup menu implementation is necessary for such a menu to appear.
这篇关于有动作条中的两个单选项将无法正常工作，但附加一个弹出菜单，而不是也不管用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！