用awk处理一个CSV（制表符分隔）一行一行

问题描述

限时删除！！

对不起，如果这是不可能的AWK的事，但这个事情我可以用AWK想到的。

sorry if this is impossible to do with AWK, but this is something I can think of with AWK.

我有了一个大标题部分约10列的CSV文件（制表符分隔）。内容是这样的：

I have a CSV file (tab delimited) that has about 10 columns with a big header section. The content is like this:

col1 col2 col3 col4 col5 col6 col7 col8 col9 col10

我并不需要通过col1-9过滤，而只需要通过线看col10线。 col10的每一行中的内容是这样的。

I don't need to filter by col1-9, but only need to look at col10 line by line. The content in each row of col10 is like this

int1/int2: int3,int4: int5: int6

我的过滤条件为：如果INT3 + INT4＆GT; = 30 ，我会打印出来到一个新的CSV文件，否则筛选出来（没有打印）

My filtering condition is: if int3 + int4 >= 30, I'll print it out to a new csv file, otherwise filter it out (no print).

这可能与AWK做与shell脚本（逐行读取？）组合？非常感谢您阅读我的问题

Is this possible to do with AWK in combination with shell scripts (read line by line?)? thanks a lot for reading my question

推荐答案

试试这个

awk -F'\t' -v OFS='\t' '{ t = $10
split(t,x,":")
split(x[2],a,",")
}(a[1]+a[2])>=30' oldcsv > newcsv

或较短的：

awk -F'\t' -v OFS='\t' '{t=$10; split(t,a,/[:,]/)}(a[3]+a[2])>=30' oldcsv > newcsv

没有测试，但应该工作，如果$ 10的格式是固定的。

didn't test, but should work, if the format of $10 is fixed.

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