本文介绍了在抽屉式导航中获取未定义不是函数(评估'(0,_reactNavigation.stacknavigator)')的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

限时删除!!

在我的应用程序中,我需要抽屉式导航,因为我正在使用.我已将所有内容集成到应用程序中,但出现以下错误

In my application I need drawer navigation, for that I am using sample code from this. I have integrated everything in my application, but getting the following error

并且也安装了这个.

npm install react-navigation --save

但是不知道为什么会出现此错误,所以请指导我如何解决此问题.

But don't know why this error is coming, So please guide me how to resolve this.

这是我的app.js

This is my app.js

import React, { Component } from 'react';
import { StyleSheet , Platform , View , Text , Image ,
         TouchableOpacity , YellowBox } from 'react-native';
import { DrawerNavigator, StackNavigator } from 'react-navigation';

class NavigationDrawerStructure extends Component {
  //Structure for the navigatin Drawer
  toggleDrawer = () => {
    //Props to open/close the drawer
    this.props.navigationProps.toggleDrawer();
  };
  render() {
    return (
      <View style={{ flexDirection: 'row' }}>
        <TouchableOpacity onPress={this.toggleDrawer.bind(this)}>
          {/*Donute Button Image */}
          <Image
            source={require('./image/drawer.png')}
            style={{ width: 25, height: 25, marginLeft: 5 }}
          />
        </TouchableOpacity>
      </View>
    );
  }
}

class Screen1 extends Component {
  //Screen1 Component
  render() {
    return (
      <View style={styles.MainContainer}>
        <Text style={{ fontSize: 23 }}> Screen 1 </Text>
      </View>
    );
  }
}

class Screen2 extends Component {
  //Screen2 Component
  render() {
    return (
      <View style={styles.MainContainer}>
        <Text style={{ fontSize: 23 }}> Screen 2 </Text>
      </View>
    );
  }
}

class Screen3 extends Component {
  //Screen3 Component
  render() {
    return (
      <View style={styles.MainContainer}>
        <Text style={{ fontSize: 23 }}> Screen 3 </Text>
      </View>
    );
  }
}

const FirstActivity_StackNavigator = StackNavigator({
  //All the screen from the Screen1 will be indexed here
  First: {
    screen: Screen1,
    navigationOptions: ({ navigation }) => ({
      title: 'Screen1',
      headerLeft: <NavigationDrawerStructure navigationProps={navigation} />,
      headerStyle: {
        backgroundColor: '#FF9800',
      },
      headerTintColor: '#fff',
    }),
  },
});

const Screen2_StackNavigator = StackNavigator({
  //All the screen from the Screen2 will be indexed here
  Second: {
    screen: Screen2,
    navigationOptions: ({ navigation }) => ({
      title: 'Screen2',
      headerLeft: <NavigationDrawerStructure navigationProps={navigation} />,
      headerStyle: {
        backgroundColor: '#FF9800',
      },
      headerTintColor: '#fff',
    }),
  },
});

const Screen3_StackNavigator = StackNavigator({
  //All the screen from the Screen3 will be indexed here
  Third: {
    screen: Screen3,
    navigationOptions: ({ navigation }) => ({
      title: 'Screen3',
      headerLeft: <NavigationDrawerStructure navigationProps={navigation} />,
      headerStyle: {
        backgroundColor: '#FF9800',
      },
      headerTintColor: '#fff',
    }),
  },
});

const DrawerNavigatorExample = DrawerNavigator({
  //Drawer Optons and indexing
  Screen1: { //Title
    screen: FirstActivity_StackNavigator,
  },

  Screen2: {//Title
    screen: Screen2_StackNavigator,
  },

  Screen3: {//Title
    screen: Screen3_StackNavigator,
  },
});
export default DrawerNavigatorExample;

const styles = StyleSheet.create({
  MainContainer: {
    flex: 1,
    paddingTop: 20,
    alignItems: 'center',
    marginTop: 50,
    justifyContent: 'center',
  },
});

这是package.json

And this is package.json

{
  "name": "DrawerNavigation",
  "version": "0.0.1",
  "private": true,
  "scripts": {
    "start": "node node_modules/react-native/local-cli/cli.js start",
    "test": "jest"
  },
  "dependencies": {
    "react": "16.6.1",
    "react-native": "0.57.5",
    "react-native-vector-icons": "^6.1.0",
    "react-navigation": "^3.0.0"
  },
  "devDependencies": {
    "babel-jest": "23.6.0",
    "jest": "23.6.0",
    "metro-react-native-babel-preset": "0.49.2",
    "react-test-renderer": "16.6.1"
  },
  "jest": {
    "preset": "react-native"
  }
}

如果我按照下面的示例进行采样,也会遇到相同的错误.

If I follow bellow sample also getting same error.

https://medium.com /@ mehulmistri/drawer-navigation-with-custom-side-menu-react-native-fbd5680060ba

任何人都可以帮助

推荐答案

我希望这一点对您有所帮助,对我有帮助!

I hope this one will help you, It helped me!

App.js

import { createStackNavigator, createAppContainer } from 'react-navigation';
import HomeScreen from './yourScreenPath';

const AppNavigator = createStackNavigator({
  Home: { screen: HomeScreen }
});

export default createAppContainer(AppNavigator);

查看链接:反应导航

修改:

较新的版本没有createStackNavigator,现在可以在 React Navigation Stack .

The newer versions doesn't have createStackNavigator, now the function can be found at React Navigation Stack.

这篇关于在抽屉式导航中获取未定义不是函数(评估'(0,_reactNavigation.stacknavigator)')的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

1403页,肝出来的..

09-06 19:28