Android-以编程方式选择GridView的项目?

问题描述

限时删除！！

我想在 setAdapter()方法之后单击某个项目.

I want to perform a click on an item after setAdapter() method.

考虑一下，如果您已在 Activity 中全局声明并初始化了 Button ，那么您可以在该活动的任何范围内以编程方式对其进行单击，并且侦听器将起作用.我想要类似的东西，以便能够对我的 GridView 中的任何项目进行点击.

Consider if you have declared and initialized a Button in your Activity globally then you can perform a click on it programmatically from any scope of that activity and the listener will work. I want something similar like that, to be able to perform a click on any item of my GridView.

到目前为止，我已经一个一个地尝试了以下所有方法，但是它们似乎都不起作用，我尝试了不同的堆栈问题，但是甚至没有一个答案对我有用. iconsGrid.setSelection(2); ， iconsGrid.setSelected(true); ， iconsGrid.performClick(); ， iconsGrid.performItemClick(iconsGrid，2，2); ， iconsGrid.performItemClick(iconsGrid，2，iconsGrid.getItemIdAtPosition(2)); ，

So far i have tried all of the below methods one by one but none of them seems to work, i tried different stack questions but not even a single answer worked for me. iconsGrid.setSelection(2);, iconsGrid.setSelected(true);, iconsGrid.performClick();, iconsGrid.performItemClick(iconsGrid, 2, 2);, iconsGrid.performItemClick(iconsGrid, 2, iconsGrid.getItemIdAtPosition(2));,

//Activity
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    mTextView = (TextView) findViewById(R.id.txt);
    Integer[] resource_icons = {
            R.drawable.ic_attachment,
            R.drawable.ic_attachment,
            R.drawable.ic_attachment,
            R.drawable.ic_attachment,
            R.drawable.ic_attachment,
            R.drawable.ic_attachment };

    GridView iconsGrid = (GridView) findViewById(R.id.gv_icons);
    IconGridAdapter iconAdapter = new IconGridAdapter(this, resource_icons);
    iconsGrid.setAdapter(iconAdapter);
   /*
    * I want to perform a click here
    */
}

//Adapter
@Override
public View getView(int position, View convertView, ViewGroup parent) {
    LayoutInflater li;
    View grid;
    if (convertView == null) {
        grid = new View(mContext);
        li = ((Activity) mContext).getLayoutInflater();
        grid = li.inflate(R.layout.grid_cell_imageview, parent, false);
    } else {
        grid = (View) convertView;
    }

    ImageView imageView = (ImageView) grid.findViewById(R.id.image);
    imageView.setImageResource(imageId[position]);

    return grid;
}

推荐答案

好的，让我们这样做

在适配器中声明一个字段，说

declare one field in your adapter say

private int selectedPosition=-1;

现在为此创建一个setter

now create a setter for this

private void setSelectedPosition(int position)
{
selectedPosition=position;
}

现在在您的getView方法中

Now in your getView method

if(position==selectedPosition)
    {
    grid.setSelected(true);

    //OR

    grid.setBackgroundColor(<Some Color>);
    }

现在设置适配器后

adapter.setSelectedPosition(<your desired selected item position>);

adapter.notifyDataSetChanged();

这篇关于Android-以编程方式选择GridView的项目?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！

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