RSA_private_decrypt返回-1

问题描述

限时删除！！

我尝试使用RSA算法加密简单文本。我的代码有问题。

  RSA * _RSA; 
 unsigned char text [2560] =A; 
 unsigned char sectext [2560]; 
 unsigned char decrypttext [2560]; 
 int i = 0; 
 
 _RSA = RSA_generate_key（1024，65537，NULL，NULL）; 
 i = RSA_public_encrypt（1，text，sectext，_RSA，RSA_PKCS1_OAEP_PADDING）; 
 i = RSA_private_decrypt（1，sectext，decrypttext，_RSA，RSA_PKCS1_OAEP_PADDING）; 
 RSA_free（_RSA）; 
  

RSA_public_encrypt 的返回值为128，这是密文的大小。 RSA_private_decrypt 返回-1，这是一个错误。如果我尝试显示恢复的文本，那么我什么都没有。

为什么 RSA_private_decrypt 返回-1？ p>

解决方案

你不应该将1传递给 RSA_private_decrypt ，而是阻止你的长度正在尝试解密，即。返回值 RSA_public_encrypt = 128.当您解密时，您不知道明文的长度！

这个完整的示例程序导致：

  128加密。 
 1来自解密：'A'
  

资料来源：

  #include< openssl / rsa.h> 
 #include< openssl / engine.h> 
 #include< stdio.h> 
 
 int main（int argc，char ** argv）
 {
 RSA * myRSA; 
 unsigned char cleartext [2560] =A; 
 unsigned char encrypted [2560] = {0}; 
 unsigned char decryptpted [2560] = {0}; 
 int resultEncrypt = 0; 
 int resultDecrypt = 0; 
 
 myRSA = RSA_generate_key（1024，65537，NULL，NULL）; 
 resultEncrypt = RSA_public_encrypt（1 / * strlen（cleartext）* /，cleartext，encrypted，myRSA，RSA_PKCS1_OAEP_PADDING）; 
 printf（％d from encrypt.\\\
，resultEncrypt）; 
 resultDecrypt = RSA_private_decrypt（128 / * resultEncrypt * /，加密，解密，myRSA，RSA_PKCS1_OAEP_PADDING）; 
 printf（％d from decrypt：'％s'\\\
，resultDecrypt，decryptpted）; 
 RSA_free（myRSA）; 
 
 return 0; 
} 
  

I try to encrypt simple text with RSA algorithm. I have a problem with my code.

RSA        *_RSA ;
unsigned char text[2560] = "A";
unsigned char sectext[2560];
unsigned char decrypttext[2560];
int i = 0;

_RSA = RSA_generate_key ( 1024, 65537, NULL, NULL );
i = RSA_public_encrypt ( 1, text,    sectext,     _RSA, RSA_PKCS1_OAEP_PADDING );
i = RSA_private_decrypt( 1, sectext, decrypttext, _RSA, RSA_PKCS1_OAEP_PADDING);
RSA_free ( _RSA );

The return value of RSA_public_encrypt is 128, which is the size of the ciphertext. RSA_private_decrypt returns -1, which is an error. If I try to display the recovered text then I get nothing.

Why is RSA_private_decrypt returning -1?

解决方案

You should not pass 1 to RSA_private_decrypt but the length of the block you are trying to decrypt, ie. the return value of RSA_public_encrypt = 128. You do not know the length of the cleartext when you are decrypting!

This complete sample program results in:

128 from encrypt.
1 from decrypt: 'A'

Source:

#include <openssl/rsa.h>
#include <openssl/engine.h>
#include <stdio.h>

int main(int argc, char **argv)
{
    RSA *myRSA;
    unsigned char cleartext[2560] = "A";
    unsigned char encrypted[2560] = { 0 };
    unsigned char decrypted[2560] = { 0 };
    int resultEncrypt = 0;
    int resultDecrypt = 0;

    myRSA = RSA_generate_key ( 1024, 65537, NULL, NULL );
    resultEncrypt = RSA_public_encrypt ( 1 /* strlen(cleartext) */, cleartext, encrypted, myRSA, RSA_PKCS1_OAEP_PADDING );
    printf("%d from encrypt.\n", resultEncrypt);
    resultDecrypt = RSA_private_decrypt( 128 /* resultEncrypt */, encrypted, decrypted, myRSA, RSA_PKCS1_OAEP_PADDING);
    printf("%d from decrypt: '%s'\n", resultDecrypt, decrypted);
    RSA_free ( myRSA );

    return 0;
}

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