需求：XML为例如以下样式，如今我仅仅想取得timer以下的5000和60000.
解决的方法例如以下：
<?xml version="1.0" encoding="UTF-8"? >
<we> <message id="1001">
<String>Id</String>
<String>name</String>
<String>sfz</String>
<String>w</String>
</message>
<!-- 定时任务设置 -->
<timer>
<delay>5000</delay>
<period>60000</period>
</timer>
</we>
/**
* 解析指定xml路径下的信息
*
* @param fileName
* xml文件路径
* @param xmlPath
* xml里元素路径
* @return 返回map,如map.get("delay")就可取到以下的5000
* <timer>
<delay>5000</delay>
<period>60000</period>
</timer>
*/
public Map parserXml(String fileName, String xmlPath) {
Document document;
Map map = new HashMap();
try {
document = getDocument(fileName);
List list = document.selectNodes(xmlPath);
for (int i = 0; i < list.size(); i++) {
Element timer = (Element) list.get(i);
for(Iterator j = timer.elementIterator();j.hasNext();){
Element node = (Element) j.next();
//System.out.println(node.getName() + ":" + node.getText());
map.put(node.getName(), node.getText());
}
}
} catch (DocumentException e) {
e.printStackTrace();
}
return map;
} private Document getDocument(String xmlFile) throws DocumentException {
SAXReader reader = new SAXReader();
return reader.read(xmlFile);
}
public static void main(String[] args) {
Dom4jDemo d = new Dom4jDemo();
String relativelyPath = new File(Dom4jDemo.class.getResource("/")
.getPath()).getParent() + File.separator + "src\\sysConfig.xml";
System.out.println(relativelyPath);
// d.createXml(relativelyPath);
/*List list = d.parserXml(relativelyPath);
for (int i = 0; i < list.size(); i++) {
System.out.println(list.get(i));
}*/
String xmlPath = "/we/timer";
Map map = d.parserXml(relativelyPath, xmlPath);
System.out.println(map.get("delay"));
}