问题描述
任何人都知道转换从< BufferedImage>返回的RGBint值的简单方法。 getRGB（i，j）到一个灰度值？
Anyone know of a simple way of converting the RGBint value returned from <BufferedImage> getRGB(i,j) into a greyscale value?
我只想通过使用它来分解它们来平均RGB值;
I was going to simply average the RGB values by breaking them up using this;
int alpha = (pixel >> 24) & 0xff;
int red = (pixel >> 16) & 0xff;
int green = (pixel >> 8) & 0xff;
int blue = (pixel) & 0xff;
然后是红色，绿色，蓝色。
and then average red,green,blue.
但我觉得这样一个简单的操作我一定会错过一些东西...
But i feel like for such a simple operation I must be missing something...
在对一个不同的问题做出了很好的回答之后，我应该清楚一下想要。
After a great answer to a different question, I should clear up what i want.
我想从getRGB（i，j）返回RGB值，并将其转换为0-255范围内的白色值，表示那个像素的黑暗。
I want to take the RGB value returned from getRGB(i,j), and turn that into a white-value in the range 0-255 representing the "Darkness" of that pixel.
这可以通过平均等来实现，但我正在寻找一个OTS实现来节省几行。
This can be accomplished by averaging and such but I am looking for an OTS implementation to save me a few lines.
推荐答案
这并不像听起来那么简单，因为
this isn't as simple as it sounds because there is no 100% correct answer for how to map a colour to greyscale.
方法我用的是将RGB转换为HSL然后转换为S部分（并且可选地转换回RGB），但这可能不是您想要的。 （它相当于最高和最低rgb值的平均值，因此与所有3的平均值略有不同）
the method i'd use is to convert RGB to HSL then 0 the S portion (and optionally convert back to RGB) but this might not be exactly what you want. (it is equivalent to the average of the highest and lowest rgb value so a little different to the average of all 3)
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