问题描述
在我的程序中说，我有这个paint()方法.我的愿望是创建所绘制矩形的图像(使用 for 循环).我尝试了下面的方法，它确实给了我那些矩形(蓝色)，但背景全是黑色.当我在不创建图像的情况下运行程序时，只需在 JFrame 上绘制矩形，背景为白色.我怎样才能解决这个问题.?
say in my program, i have this paint() method. my wish is to create an image of the rectangles that are drawn (with the for loop). I tried the method below and it did give me those rectangles (blue color), but the background is all black. When I run program without creating image, just drawing the rect on a JFrame, the background is white. How can i fix this. ?
public void paint(Graphics g) {
super.paint(g);
BufferedImage image = new BufferedImage(100, 100, BufferedImage.TYPE_INT_RGB);
g = Image.getGraphics(); <<<----- is this correct?
g.setColor(Color.blue);
for ( ..... ) {
g.fillRect(X , Y, width , height);
....
}
try {
ImageIO.write(image, "jpg", new File("CustomImage.jpg"));
}catch (IOException e) {
e.printStackTrace();
}
}
推荐答案
图像中的背景是黑色的，因为除了矩形中的像素之外，您没有为任何像素指定值.BufferedImage 开始时每个像素的 RGB 为 (0, 0, 0)，即黑色.要为整个图像提供白色背景，只需用白色填充图像的整个矩形即可.
The background is black in your image because you are not giving any pixels a value except those in the rectangles. The BufferedImage is starting out with every pixel having RGB of (0, 0, 0), which is black. To give the entire image a white background, simply fill the entire rectangle that is the image with white.
BufferedImage image = new BufferedImage(100, 100, BufferedImage.TYPE_INT_RGB);
g = image.createGraphics(); // not sure on this line, but this seems more right
g.setColor(Color.white);
g.fillRect(0, 0, 100, 100); // give the whole image a white background
g.setColor(Color.blue);
for( ..... ){
g.fillRect(X , Y, width , height );
....
}
请注意，我的回答是将图像写入白色背景的文件，而不是绘制到黑色背景的 JFrame.我不完全确定你想要哪一个.
Note that my answer is about writing the image to a file with a white background, not about drawing to the JFrame with a black background. I'm not entirely sure which one you wanted.
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