问题描述
给出以下代码
#!/usr/bin/perl
use Data::Dumper;
my %hash;
my @colos = qw(ac4 ch1 ir2 ird kr3);
foreach my $colo (@colos) {
if(exists $hash{output}{$colo}) {
print "$colo is in the hash\n";
}
}
print Dumper(\%hash);
我创建了一个空哈希.我有一个数组,里面有一些缩写.如果我遍历数组以查看这些家伙是否在哈希中,则不会向STDOUT显示任何内容,但是出于某种原因会创建$ hash {output}.这根本不符合逻辑.我正在做的只是一个if存在.我哪里出问题了?
I have an empty hash that is created. I have an array with a few abbreviations in it. If I cycle through the array to see if these guys are in the hash, nothing is displayed to STDOUT which is expected but the $hash{output} is created for some reason. This does not make sense. All I am doing is an if exists. Where did I go wrong?
推荐答案
exists
在给定哈希中查找哈希元素.您的代码正在自动生成哈希
%{ $hash{output} }
并检查该哈希中是否存在键为$colo
的哈希元素.
exists
looks for a hash element in a given hash. Your code is autogenerating the hash
%{ $hash{output} }
and checking if a hash element with key $colo
is existing in that hash.
请尝试以下操作:
if(exists $hash{output}{$colo}) {
更改为
if(exists $hash{output} and exists $hash{output}{$colo}) {
您当然可以编写一个隐藏代码中复杂性的子程序.
You can, of course, write a sub that is hiding that complexity from your code.
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