如何在datagridview中显示图像?C#

问题描述

限时删除！！

我正在使用 Visual Studio Express 2010 用 C# 开发桌面应用程序.

我在 MySQL 中有一个名为 Products 的表，其中包含 3 个字段:

ID -> Product_Name -> product_image

字段 product_Image 存储我硬盘中的图像路径(不是图像本身)

一个记录的例子是:

0001 --- 鼠标垫 XYZ ---- c:imagesmousepad.jpg

我想知道如何为我的 SQL 查询中的每条记录填充一个 datagridview 来显示 ID、产品名称，尤其是产品图片.

我发现的所有示例都使用了手动数据插入，但我正在寻找一个示例来使用来自 SQL 查询的数据填充 datagridview，而不是手动插入.

感谢您的帮助，但无法直接应用解决方案.

我的表单上已经有一个 datagridview，我不需要在运行时创建.

我需要这样的东西(我会写一个通用的方式)

returnMySQL = "select * from products";而(返回MySQL){用 ID、产品名称、产品图片填充数据网格}

解决方案

使用以下代码:

位图img；img = new Bitmap(@"c:imagesmousepad.jpg");//创建带有 Image 列的 DGVDataGridView dgv = 新 DataGridView();this.Controls.Add(dgv);DataGridViewImageColumn imageCol = new DataGridViewImageColumn();dgv.Columns.Add(imageCol);//添加一行并将其值设置为图像dgv.Rows.Add();dgv.Rows[0].Cells[0].Value = img;

参考链接.>

I am developing an application in C # for desktop using Visual Studio Express 2010.

I have a table in MySQL called Products with 3 fields:

The field product_Image stores the image path in my hard drive (not the image itself)

An example of a record would be:

I wonder how fill a datagridview that shows the ID, Produt name, and - especially - the product image for each record in my SQL query.

All the examples I found were used manual data inserts, but I am looking for an example to fill the datagridview with data from a SQL query, not a manual insertion.

Edit:

Thank you for help, but could not directly apply the solutions.

I already have a datagridview on my form, I have no need to create in runtime.

I need something like that (I'll write a generic way)

returnMySQL = "select * from products";

while (returnMySQL)
{
    fill datagrid with ID, product name, product image
}

解决方案

Use following Code:

Bitmap img;

img = new Bitmap(@"c:imagesmousepad.jpg");

// Create the DGV with an Image column

DataGridView dgv = new DataGridView();

this.Controls.Add(dgv);

DataGridViewImageColumn imageCol = new DataGridViewImageColumn();

dgv.Columns.Add(imageCol);

// Add a row and set its value to the image

dgv.Rows.Add();

dgv.Rows[0].Cells[0].Value = img;

Referance LINK .

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