问题描述
我以doc1/*.png作为第一个参数运行脚本，但该脚本被转换为doc1/image1.png.
I run my script with doc1/*.png as first argument, but it gets converted to doc1/image1.png.
如何让Python看到确切的参数?
How can I let Python see the exact argument?
img_list = []
print sys.argv[1]
x = sys.argv[1]
img_list = [img for img in glob.glob(x)]
推荐答案
在大多数Linux外壳程序(bash，sh，fish，...)上，星号由外壳程序处理. *转换为文件列表的事实已经在外壳程序级别上完成.
On most linux shells (bash, sh, fish,...), the asterisk is handled by the shell. The fact that the * is converted to a list of files is already done at the shell level.
如果您写:
python file.py doc/*.png
外壳本身会将doc/*.png转换为"doc/1.png" "doc/2.png"(因此，它在doc目录中找到的.png文件列表.
The shell itself will translate doc/*.png into "doc/1.png" "doc/2.png" (so a list of .png files it finds in the doc directory.
您应使用引号将星号传递，例如:
python file.py 'doc/*.png'
标准Windows shell 不不对文件名使用通配符.
The standard Windows shell does not do wildcards for file names.
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