当没有更多连接时 asyncore.loop 不会终止

问题描述

我正在按照一些示例代码使用 asyncore 此处，只需为 asyncore.loop 设置一个 timeout 值，如下面的完整示例所示:

I am following some example code to use asyncore here, only having set a timeout value for asyncore.loop as in the following full example:

import smtpd
import asyncore

class CustomSMTPServer(smtpd.SMTPServer):

    def process_message(self, peer, mailfrom, rcpttos, data):
        print 'Receiving message from:', peer
        print 'Message addressed from:', mailfrom
        print 'Message addressed to  :', rcpttos
        print 'Message length        :', len(data)
        return

server = CustomSMTPServer(('127.0.0.1', 1025), None)

asyncore.loop(timeout = 1)

我预计 1 秒后会发生超时，但事实并非如此.代码运行时间超过一秒钟.我在这里错过了什么?

I have expected that a timeout occurs after 1 second, but this is not the case. The code runs much longer for than one second. What am I missing here?

推荐答案

我真的不知道 asyncore.loop() 的 timeout 参数是否真的是为了在指定时间后超时函数调用 asyncore.loop()，但这里是一个收据，使该函数在指定时间后超时(用 asyncore.loop() 替换该行code> 在示例代码中):

I really do not know if the timeout argument to asyncore.loop() really is meant to timeout the function call asyncore.loop() after the specified time, but here is a receipt to make that function timeout after a specified time (replacing the line with asyncore.loop() in the example code):

import signal

class TimeoutError(Exception): pass

# define the timeout handler
def handler(signum, frame):
    raise TimeoutError()

# set the timeout handler and the signal duration
signal.signal(signal.SIGALRM, handler)
signal.alarm(1)
try:
    asyncore.loop()
except TimeoutError as exc:
    print "timeout"
finally:
    signal.alarm(0)

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