如何删除一列，并从C＃锯齿状排阵

问题描述

我有以下dists中的锯齿形阵列

  INT [] [] dists中=新的INT [] [] 
 {
新INT [] {0,2,3,5,2}，
新INT [] {2,0,1,3,5}，
新INT [] {3,1,0,4,4}，
新INT [] {5,3,4,0,2}，
新INT [] {2,5,4,2 ，0} 
}; 
  

现在我想创建名为 finalDists 当我从 dists中的原始数组中删除第3行3列。我的意思是我想终于有如下交错数组：

  INT [] [] finalDists =新INT [] [] 
 {
新INT [] {0,2,5,2}，
新INT [] {2,0,3,5}，
新INT [] {5,3 ，0,2}，
新INT [] {2,5,2,0} 
}; 
  





我很困惑如何处理这个问题，所有的感谢您的帮助之前

解决方案

  INT [] [] = finalDists dists.Where（（ARR，I）=>！I = 2）//跳过一行3＃
。选择（ARR => arr.Where（（项目，I）=>！I = 2）//跳过山口3＃
 .ToArray（） ）
 .ToArray（）; 
  

I have following jagged array of "dists"

int[][] dists = new int[][]
{
    new int[]{0,2,3,5,2},
    new int[]{2,0,1,3,5},
    new int[]{3,1,0,4,4},
    new int[]{5,3,4,0,2},
    new int[]{2,5,4,2,0}
};

now I want to create another jagged array named as finalDists when I remove the 3rd row and 3rd column from original array of dists. I mean I want finally have following jagged array:

int[][] finalDists = new int[][]
{
    new int[]{0,2,5,2},
    new int[]{2,0,3,5},
    new int[]{5,3,0,2},
    new int[]{2,5,2,0}
}; 

I am confused how to handle this issue, before all thanks for your help

解决方案

int[][] finalDists = dists.Where((arr, i)=>i!=2) //skip row#3
                          .Select(arr=>arr.Where((item,i)=>i!=2) //skip col#3
                                          .ToArray())
                          .ToArray();

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