本文介绍了如何在clang中打印完全合格的Expr?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用clang 8.0.1开发反射工具.现在,我需要使用所有完全合格的名称打印Expr.
I'm working on my reflection tool with clang 8.0.1. And right now I need to print Expr with all names fully qualified.
我已经尝试过将FullyQualifiedName位设置为true的内置prettyPrint函数.但是它仍然给出错误的结果.
I already tried builtin prettyPrint function with FullyQualifiedName bit set to true. But it still gives incorrect result.
对于这段代码:
namespace math {
struct Transform {
float val;
[[custom_attr(&Transform::public_val)]]
void foo();
};
}
它给了我
&Transform::public_val
代替
&math::Transform::public_val
还有
static_cast<float (*)(const Transform&)>(Transform::static_overload)
作为custom_attr的值,它给了我
as value of custom_attr it gives me
static_cast<float (*)(const math::Transform &)>(Transform::static_overload)
(仅Transform::static_over
)
这是我的打印代码:
std::string get_string(const Expr *expr, const ASTContext &Context) {
PrintingPolicy print_policy(Context.getLangOpts());
print_policy.FullyQualifiedName = 1;
print_policy.SuppressScope = 0;
print_policy.SuppressUnwrittenScope = 0;
std::string expr_string;
llvm::raw_string_ostream stream(expr_string);
expr->printPretty(stream, nullptr, print_policy);
stream.flush();
return expr_string;
}
推荐答案
我所需要做的只是指定PrintCanonicalTypes
标志.这是从Expr获取字符串的功能:
All I needed is to specify PrintCanonicalTypes
flag. Here is function for getting string from Expr:
std::string getFullyQualified(const Expr *expr,
const ASTContext &Context) {
static PrintingPolicy print_policy(Context.getLangOpts());
print_policy.FullyQualifiedName = 1;
print_policy.SuppressScope = 0;
print_policy.PrintCanonicalTypes = 1;
std::string expr_string;
llvm::raw_string_ostream stream(expr_string);
expr->printPretty(stream, nullptr, print_policy);
stream.flush();
return expr_string;
}
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