将TableViewCell推送到另一个ViewController时出错 | 将TableViewCell推送到另一个ViewControll

本文介绍了将TableViewCell推送到另一个ViewController时出错的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我试图将数据从TableViewCell传递到另一个ViewController.但是没有数据显示在另一个ViewController中.这是我的代码

I trying to pass the data from TableViewCell to the another ViewController.But No data Displaying in the another ViewController.here is my Code

-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath{


   PeripheralManager *objSelected=[device objectAtIndex:indexPath.row];

   [self prepareForSegue:@"TableDetails" sender:objSelectedDevice];
 }


-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{


   if ([segue.identifier isEqualToString:@"TableDetails"])
   {


   DetailViewController *detail=segue.destinationViewController;
   detail.dataArray=device;
   }

 }

错误消息

nested push animation can result in corrupted navigation bar
2012-10-24 12:01:39.805 [3182:707] nested push animation can result in corrupted navigation bar
2012-10-24 12:01:40.164 [3182:707] Finishing up a navigation transition in an unexpected state. Navigation Bar subview tree might get corrupted.
2012-10-24 12:01:40.167 [3182:707] Finishing up a get navigation transition in an unexpected state. Navigation Bar subview tree might corrupted.

推荐答案

删除您的多余代码仅这样做-

Remove your extra code Only do this-

在DetailViewController.h

@property(nonatomic, retain)NSMutableArray *dataArray;

在DetailViewController.m

@synthesize dataArray = _dataArray;

现在在TableViewController.m中，只需编写此内容-

Now In TableViewController.m Just write this -

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
   if([segue.identifier isEqualToString:@"TableDetails"])
   {
     DetailViewController *detailViewObject = segue.destinationViewController;
     detailViewObject.dataArray = anyArray;
   }
}

我在这里通过NSMutableArray.

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